Question

ASAP please

Answer 1

Answer:

$V = \dfrac{1}{3}(3.14)(2^2)(3) - \dfrac{4}{3}(3.14)(0.25^3)$

Step-by-step explanation:

The volume that can be filled with flavored ice is the volume of the cone minus the volume of the gum sphere.

radius = diameter/2

$V_{cone} = \dfrac{1}{3} \pi r_c^2 h$

$V_{sphere} = \dfrac{4}{3} \pi r_s^3$

$V = V_{cone} - V_{sphere}$

$V = \dfrac{1}{3} \pi r_c^2 h - \dfrac{4}{3} \pi r_s^3$

$V = \dfrac{1}{3} \pi (2~in.)^2 \times 3~in. - \dfrac{4}{3} \pi (0.5~in.)^3$

$V = \dfrac{1}{3}(3.14)(2^2)(3) - \dfrac{4}{3}(3.14)(0.25^3)$

Answer 2

Answer:

Step-by-step explanation:

The volume that can be filled with flavored ice is the volume of the cone minus the volume of the gum sphere.

radius = diameter/2