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stiv31 [10]
3 years ago
11

Jackson and Jonah are both swimming. Jackson swims at 1350 meters per hour. Jonah swims at a speed of 1250 millimeters per secon

d. Who swam faster in cm/min? How much faster?
A. Jackson, 2250 cm/min
B. Jonah, 7500 cm/min
C. Jackson, 5250 cm/min
D. Jonah, 5250 cm/min
Mathematics
1 answer:
Vladimir [108]3 years ago
7 0

For this question we will use the following relations.

100 centimeters=1 meter (or 1 centimeter= 0.01 meter)

10 millimeter=1 centimeter (or 1 mm=0.1 cm)

60 minutes = 1 hour (or 1 min=\frac{1}{60} hour)

Now, Jackson's speed is 1350 meters per hour. This can be converted to cm per minute as follows:

\frac{1350 m}{1 h}=\frac{1350\times 100 cm}{60 min}=2250 cm/min...Equation 1

Likewise, Jonah's swim speed in cm/min can be calculated as:

\frac{1250 mm}{1 s}=\frac{1250\times 0.1 cm}{\frac{1}{60}min } =\frac{125\times 60 cm}{1 min}=7500cm/min...Equation 2

As we can see clearly after comparing Equation 1 and Equation 2, Jonah's swim speed of 7500 cm/min is faster than that of Jackson.

Thus, option B is correct.

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In a choir, the ratio of boys to girls is 5 to 6. There are 10 boys in the choir. What is the total number of boys and girls in
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Step-by-step explanation:

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tl:dr: 5 *2 = 10 so 6*2 = 12

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Which sequence of transformations will verify that EFGH and quadrilateral EFGH and quadrilateral E'F'G'H are congruent?
levacccp [35]

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<h3>How to carry out transformations?</h3>

From online resources gotten about this question, for quadrilateral EFGH and quadrilateral E'F'G'H to be congruent, what we must do first is to rotate 180° counterclockwise around the origin and then move EFGH onto E'F'G'H'.

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5 0
2 years ago
Suppose Sally has $28.00 in her bank account and starts saving $18.25 every week. Her friend Suzy has $161.00 in her bank accoun
Elza [17]

a.

Sally has $28.00 in her bank account and starts saving $18.25 every week.

Let x represent the number of weeks from when he have $28.00 in her account.

and y represent the amount in her account at week x;

We can write the function of the case as;

y=mx+b

where m is the amount she saves every week, and b the initial amount in her account.

\begin{gathered} m=\text{ \$18.25} \\ b=\text{ \$28.00} \end{gathered}

So, the function will be;

y=18.25x+28

b.

Her friend Suzy has $161.00 in her bank account and is withdrawing $15 every week.​

Using the same rule as in a above;

\begin{gathered} m=-15\text{ (withdrawing is negative)} \\ b=161 \end{gathered}

The function will be;

y=-15x+161

c.

The graph of the two functions is shown below;

d.

The point where the two lines intersect is shown in the graph above.

The point is at;

(4,101)

Which is at week 4 and balance $101.

e.

The point at which they intersect is the point where they both have the same values.

It is the week when both Sally and Suzy have the same amount in there account.

So, at the fourth week (week 4) Sally and Suzy both have $101 in their account

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1 year ago
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