1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
barxatty [35]
3 years ago
11

Jack's bowling score is 20 less than 3 times Jill's

Mathematics
1 answer:
babymother [125]3 years ago
3 0

Jill's score is 80. Jack's score is 140.

You might be interested in
Which expression is equivalent to the area of metal sheet required to make this square-shaped traffic sign? I WILL GIVE BRAINLYI
Dmitry_Shevchenko [17]

Answer:

4x^2+4x-1

Step-by-step explanation:

6 0
2 years ago
Simprury<br>20 s)<br>2<br>6 600J​
earnstyle [38]

Answer:

opo miss sorry di ko po Alam yan

sorry

po

5 0
2 years ago
Prove the following by induction. In each case, n is apositive integer.<br> 2^n ≤ 2^n+1 - 2^n-1 -1.
frutty [35]
<h2>Answer with explanation:</h2>

We are asked to prove by the method of mathematical induction that:

2^n\leq 2^{n+1}-2^{n-1}-1

where n is a positive integer.

  • Let us take n=1

then we have:

2^1\leq 2^{1+1}-2^{1-1}-1\\\\i.e.\\\\2\leq 2^2-2^{0}-1\\\\i.e.\\2\leq 4-1-1\\\\i.e.\\\\2\leq 4-2\\\\i.e.\\\\2\leq 2

Hence, the result is true for n=1.

  • Let us assume that the result is true for n=k

i.e.

2^k\leq 2^{k+1}-2^{k-1}-1

  • Now, we have to prove the result for n=k+1

i.e.

<u>To prove:</u>  2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Let us take n=k+1

Hence, we have:

2^{k+1}=2^k\cdot 2\\\\i.e.\\\\2^{k+1}\leq 2\cdot (2^{k+1}-2^{k-1}-1)

( Since, the result was true for n=k )

Hence, we have:

2^{k+1}\leq 2^{k+1}\cdot 2-2^{k-1}\cdot 2-2\cdot 1\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{k-1+1}-2\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-2

Also, we know that:

-2

(

Since, for n=k+1 being a positive integer we have:

2^{(k+1)+1}-2^{(k+1)-1}>0  )

Hence, we have finally,

2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Hence, the result holds true for n=k+1

Hence, we may infer that the result is true for all n belonging to positive integer.

i.e.

2^n\leq 2^{n+1}-2^{n-1}-1  where n is a positive integer.

6 0
3 years ago
Help Asap Pls Hurry I Will Give Brainliest!
dexar [7]
The answer is B
step by step explanation:
4 0
2 years ago
Read 2 more answers
Plz help i just dont get and plz do not put a file its annoying
8090 [49]

Answer:

Hello! Your answer would be, BELOW!

Step-by-step explanation:

A)

40

D)

Hope I helped! Ask me anything if you have more questions! Have a nice mourning! Brainiest plz! Hope you make an 100%! -Amelia♥

7 0
2 years ago
Other questions:
  • The function h is defined by h(x)=60÷x−r, where r is a constant. Find r, if the graph of h passes through the point (−6,−20).
    6·1 answer
  • HURRY DUE IN 20 MINUTES Use the rules of exponents to simplify the expressions. Match the expression with its equivalent value.
    13·1 answer
  • What is the ratio as a fraction in lowest term for $300 to $450 ?
    11·1 answer
  • A menu offers a choice of 22 ​salads, 77 main​ dishes, and 55 desserts. How many different meals consisting of one​ salad, one m
    6·1 answer
  • A slush drink machine fills 1440 cups in 24 hours. A. Write an equation to find the number c of cups each symbol represents. I c
    10·2 answers
  • Compare and contrast the Angle Angle Similanty Postulate, the Side Side Side Similarity Theorem and the Side Angle
    14·1 answer
  • Identify the binomial
    11·1 answer
  • Hector is dividing students into groups for an HR wants to divide the boys and girls so that each group has the same number of t
    15·1 answer
  • I need to make sure I got this correct :)
    14·1 answer
  • PLEASE HELP ME OUT WITH METRIC CONVERSIONS!!!!!!
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!