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Nat2105 [25]
4 years ago
8

What is the value of 3/5 of a £1?

Mathematics
1 answer:
AlladinOne [14]4 years ago
7 0
<span>F(x)=5x+1 what is the M slope!</span>
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Which of the statements below best describes direct variation?
REY [17]
Direct variation is when one variable changes the other changes in proportion of the first, therefore all the above 
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4 years ago
Help Don't understand everything is wrong on here that I did
Alika [10]

i have know clue what it is

8 0
3 years ago
Question #3 math help please
LiRa [457]

Answer:

x = 45.6°

Step-by-step explanation:

As we can see, this is a right triangle, so there are known relationships

well to start we have to know the relationship between angles, legs and the hypotenuse

α = x°

a: adjacent

o: opposite = 5

h: hypotenuse  = 7

sin α = o/h

cos α = a/h

tan α = o/a

we see that it has (angle, hypotenuse, opposite)

is the sine

sin α = o/h

sin x = 5/7

x = sin^-1 (5/7)

x = 45.58°

if we want to round to the nearest tenth

x = 45.58° = 45.6°

4 0
3 years ago
Oneta writes an algebraic expression with three terms. The y-term has a coefficient of -3, and the x-term has a coefficient of 1
Snowcat [4.5K]

Answer:

x - 3y + z

Step-by-step explanation:

Terms are just names for objects inside the equation -- anything that isn't an operation. A coefficient the is the number a given term (variable) is being mulitpled by. In this case, -3 for y, and 1 for. x. We can deduce from this the start of the expression (x has no coeff. bc of multiplicative identity)

x - 3y

We know we are missing one term, and we also know that the third term cannot be constant, so it must be another variable. In this case I have chosen Z, in theory it shouldn't really matter but z is the best variable name in this case.

5 0
3 years ago
What is the area of the given figure?
kirza4 [7]

\huge\boxed{192\ \text{in}^2}

There are three parts to this figure: a rectangle and two triangles that are congruent.

We'll add together the area for each to get the total area.

We'll start by finding the area of the rectangle. We don't know its length, so we need to find the bases of the triangles and add them together.

We know that a^2+b^2=c^2. Substitute and solve for a:

\begin{aligned}a^2+6^2&=10^2\\a^2+36&=100\\a^2+36-36&=100-36\\a^2&=64\\\sqrt{a^2}&=\sqrt{64}\\a&=8\end{aligned}

Now, double this to get the total length of the rectangle, which is 16 inches.

The area of the rectangle is equal to its length times its height:

16\cdot9=\underline{144}

Now, we'll find the area of one of the triangles and double it since they're congruent.

The area of a triangle is one-half of its base times its height, which we then double.

2\left(\frac{1}{2}\cdot b\cdot h\right)

The 2 and the \frac{1}{2} cancel each other out.

b\cdot h

Substitute and solve:

8\cdot6=\underline{48}

Finally, add the rectangle's area to the two triangles' area.

144+48=\boxed{192}

6 0
2 years ago
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