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3 years ago

HELP PLEASE Order the numbers from LEAST to GREATEST -5/6, -1/2, 2/3

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

3 0

Answer:

-5/6,-1/2,2/3

Step-by-step explanation:

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Which trig ratio uses hypotenuse and adjacent side

e-lub [12.9K]

Answer:

It's cosine.

Step-by-step explanation:

Cosine is Adjacent / Hypotenuse.

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4 years ago

Read 2 more answers

14 brainly points: can someone pls explain to me what a subset is in a way i can understand (and pls don't just find a internet

Oksana_A [137]

Answer:

Yes

Step-by-step explanation:

B is a subset of A because if A= {0,1,2,3,4} and B= {1,2} B is a part of A and B is a smaller version of A

Don't know if this helps but this is how I learned subsets.

6 0

3 years ago

To save money, a local charity organization wants to target its mailing requests for donations to individuals who are most suppo

mars1129 [50]

Answer:

The 80% confidence interval for difference between two means is (0.85, 1.55).

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for difference between two means is:

$CI=(\bar x_{1}-\bar x_{2})\pm t_{\alpha/2,(n_{1}+n_{2}-2)}\times SE_{\bar x_{1}-\bar x_{2}}$

Given:

$\bar x_{1}=M_{1}=6.1\\\bar x_{2}=M_{2}=4.9\\SE_{\bar x_{1}-\bar x_{2}}=0.25$

Confidence level = 80%

$t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.20/2, (5+5-2)}=t_{0.10,8}=1.397$

*Use a <em>t</em>-table for the critical value.

Compute the 80% confidence interval for difference between two means as follows:

$CI=(6.1-4.9)\pm 1.397\times 0.25\\=1.2\pm 0.34925\\=(0.85075, 1.54925)\\\approx(0.85, 1.55)$

Thus, the 80% confidence interval for difference between two means is (0.85, 1.55).

3 0

3 years ago

How do I solve the equation in an interval from 0 to 2π ? 9 cos 2t = 6

Ivahew [28]

$9\cos(2t)=6\implies\cos(2t)=\dfrac23$

Using the fact that cos is 2π-periodic, we have

$\cos(2t)=\dfrac23\implies2t=\cos^{-1}\left(\dfrac23\right)+2n\pi$

That is, $\cos(\theta+2n\pi)=\cos\theta$ for any $\theta$ and integer $n$ .

$\implies t=\dfrac12\cos^{-1}\left(\dfrac23\right)+n\pi$

We get 2 solutions in the interval [0, 2π] for $n=0$ and $n=1$ ,

$t=\dfrac12\cos^{-1}\left(\dfrac23\right)\text{ and }t=\dfrac12\cos^{-1}\left(\dfrac23\right)+\pi$

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3 years ago

I need help please and thank you

Lina20 [59]

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5 0

4 years ago