Solution:
Number of times a die is rolled = 20
1 - 3=A
2 - 5=B
3 - 4=C
4 - 2=D
5 - 3=E
6 - 3=F
Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times
= Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes
= 6! × [ 3! × 5! × 4!×2!×3!×3!]
= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]
= 895795200 Ways
Answer:
y+1/2-2y-1/2=4
y-2y=4
-y=4
y=-4
Let me know if this helps!
It is less than two, so it has to be going in the direction that is below two. There is a line under the < so the dot should be filled. The answer is the third from the top. “Choice C”
your answer is
5/2
if you need it simplified its
2 1/2
and in decimal form its 2.5