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Daniel [21]
3 years ago
12

How many x-intercepts does the graph of each quadratic equation have? Show your work.

Mathematics
1 answer:
Alex73 [517]3 years ago
4 0

Answer:

Step-by-step explanation:

In each case we find the discriminant b^2 - 4ac.

If the discriminant is negative, we have two unequal, complex roots.

If the discriminant is zero. we have two equal, real roots.

If the discriminant is positive, we  have two unequal real roots.

#51:  8v^2 - 12v + 9:  the discriminant is (-12)^2 - 4(8)(9) = -144.  we have two unequal, complex roots

#52:  (-11)^2 - 4(4)(-14) = 121 + 224 = 345.  we  have two unequal real roots.

#53:  (-5)^2 - 4(7)(6) = 25 - 168 (negative).  we have two unequal, complex roots.

#54:  (4)^2 - 16 = 0.  We have two equal, real roots.

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Solve this system of linear equations.separate the x- and y-value with a comma. -6x=-4-y -7x=-22+y.
scZoUnD [109]

Answer:

(2,8)

Step-by-step explanation:

Add them together to get rid of the y.

-6x = -4 - y

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=

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Then solve for x.

-13x/-13 = -26/-13

x = 2

Now plug in the x value into either equation and solve for y.

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-14 = -22 + y

-14 + 22 = -22 + 22 + y

8 = y

So...

x = 2

y = 8

(2,8)

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