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Ronch [10]
3 years ago
10

Solve. The answer must be a fraction. Solve by substituting.

Mathematics
1 answer:
maw [93]3 years ago
4 0

Answer: x = -14/5

Step-by-step explanation: We shall begin by expanding the brackets for both sides of the equation

-2/3 (x + 2) = 1/6 (x + 6)

(-2x/3) -4/3 = (x/6) + 1

By collecting like terms we now have

(-2x/3) - (x/6) = 1 + 4/3

(-4x - x)/6 = 7/3

-5x/6 = 7/3

By cross multiplication we now have

-5x (3) = 7 (6)

-15x = 42

x = -(42/15) {simplify further by dividing the RHS by 3}

x = -14/5

Therefore x equals, minus fourteen over five (-14/5)

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Look at the figure. Which trigonometric ratio should you use to find x?
Elis [28]

Answer:

B.  Sine.

Step-by-step explanation:

We need to find the value of x which is opposite to the given angle  (50 degree).  Also we are given the length of the hypotenuse.

Sine = opposite / hypotenuse so we would use the sine.

Its worth committing this mnemonic to memory, which helps to find the required trig ratio:

SOH-CAH-TOA.

SineOpposite/Hypotenuse- CosineAdjacent/Hypotenuse-TangentOpposite/Adjacent.

4 0
3 years ago
0.4(2-q=0.2(q+7) hurry please
Lerok [7]

Answer:

q=-1

Step-by-step explanation:

.8-.4q=.2q+1.4

-.2q       -.2q

.8-.6q=1.4

-.8         -.8

-.6q= 0.6

/-.6    /-.6

q= -1

5 0
3 years ago
I need some help........
Ad libitum [116K]

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Step-by-step explanation:

6 0
3 years ago
A town has 300 residents in total, of which 5/6 are white/Caucasian Americans. How many white/Caucasian Americans reside in this
Neko [114]

Answer:

250

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
The 12th term of a sequence is 41 and the 15th term is 140. What is the nth term?
OLga [1]
An= mth term.
an=a₁+(n-1)*d

a₁₂=41
a₁₅=140

a₁₂=41
41=a₁+(12-1)*d
41=a₁+11d 
a₁+11d=41    (1)

a₁₅=140
140=a₁+(15-1)*d
140=a₁+14d 
a₁+14d=140    (2)

With the equiations (1) and (2)  build a system of equations
a₁+11d=41
a₁+14d=140

we solve it.
-(a₁+11d=41)
  a₁+14d=140
--------------------
       3d=99  ⇒d=99/3=33

a₁+11d=41
a₁+(11*33)=41
a₁+363=41
a₁=41-363=-322

an=a₁+(n-1)*d
an=-322+(n-1)*33
an=-322+33n-33
an=-355+33n

an=-355+33n

To check:
a₁₂=-355+33*12=-355+396=41
a₁₅=-355+33*15=-355+495=140.
3 0
3 years ago
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