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forsale [732]
3 years ago
9

The surface area of the cube is 54 square feet. What is the length, in feet, of one edge of the cube?​

Mathematics
1 answer:
Brut [27]3 years ago
5 0

Answer:

3 ft

Step-by-step explanation:

A cube is made of 6 equal faces each of which is a square with the same side length. The surface area of the cube is the surface area of one side multiplied by 6. We know the surface area is 54 so divide this by 6.

54/6 = 9 ft^2

Since the surface must be a square, take the square root of 9 which is 3 ft. The length of one edge of the cube is 3 ft.

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A punter kicks a football upward with an initial velocity of 48 feet per second. After how many seconds does the ball hit the gr
vfiekz [6]
H=48t-16t^2
h=32t^2
The answer is that the football travels 32t^2?
3 0
3 years ago
Find the distance between the points (-3, 11) and (5, 5).
marshall27 [118]
Formula for distance between two points:

d  = √((x₂-x₁)² + (y₂-y₁)²)

Let point 1 be (-3, 11) and point 2 be (5, 5)

Therefore x₁ = -3, y₁ = 11, x₂ =5, y₂ = 5, and substituting in the formula above.

d = √((x₂-x₁)² + (y₂-y₁)²)

   = √((5- -3)² + (5-11)²)

   = √((5+3)² + (5-11)²)

   = √((8)² + (-6)²)          8² = 8*8 = 64, (-6)² = -6*-6 = 36

   = √(64 + 36)

  = √(100)

  = 10

Distance = 10 units.
5 0
3 years ago
Please help me on this question
Tasya [4]
I think Its C because in the frequency table or table given if the heads are counted there are 6 of them and over all 10 which will make 6/10
7 0
3 years ago
382 3/10 - 191 87/100= math difficulties please answer this question
prohojiy [21]
3/10 = .3 and 87/100 = .87
382.3 - 191.87= 190.43
so the answer is 190.43

Hope this helped!! :))
7 0
3 years ago
At what point on the parabola y = 3x^2 + 2x is the tangent line parallel to the line<br> y = 10x −2?
oksian1 [2.3K]

Answer:

( \frac{4}{3} , 8 )

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 10x - 2 ← is in slope- intercept form

with slope m = 10

Parallel lines have equal slopes

then the tangent to the parabola with a slope of 10 is required.

the slope of the tangent at any point on the parabola is \frac{dy}{dx}

differentiate each term using the power rule

\frac{d}{dx} (ax^{n} ) = nax^{n-1} , then

\frac{dy}{dx} = 6x + 2

equating this to 10 gives

6x + 2 = 10 ( subtract 2 from both sides )

6x = 8 ( divide both sides by 6 )

x = \frac{8}{6} = \frac{4}{3}

substitute this value into the equation of the parabola for corresponding y- coordinate.

y = 3(\frac{4}{3} )² + 2

   = (3 × \frac{16}{9} ) + 2

   = \frac{16}{3} + \frac{8}{3}

   = \frac{24}{3}

   = 8

the point on the parabola with tangent parallel to y = 10x - 2 is ( \frac{4}{3} , 8 )

3 0
2 years ago
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