The denominator of the first term is a difference of squares, such that
4<em>a</em> ² - <em>b</em> ² = (2<em>a</em>)² - <em>b</em> ² = (2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>)
So you can write the fractions as
(4<em>a</em> ² + <em>b</em> ²)/((2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>)) - (2<em>a</em> - <em>b</em>)/(2<em>a</em> + <em>b</em>)
Multiply through the second fraction by 2<em>a</em> - <em>b</em> to get a common denominator:
(4<em>a</em> ² + <em>b</em> ²)/((2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>)) - (2<em>a</em> - <em>b</em>)²/((2<em>a</em> + <em>b</em>) (2<em>a</em> - <em>b</em>))
((4<em>a</em> ² + <em>b</em> ²) - (2<em>a</em> - <em>b</em>)²) / ((2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>))
Expand the numerator:
(4<em>a</em> ² + <em>b</em> ²) - (2<em>a</em> - <em>b</em>)²
(4<em>a</em> ² + <em>b</em> ²) - (4<em>a</em> ² - 4<em>ab</em> + <em>b</em> ²)
4<em>ab</em>
<em />
So the original expression reduces to
4<em>ab</em> / ((2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>))
or
4<em>ab</em> / (4<em>a</em> ² - <em>b</em> ²)
upon condensing the denominator again.
Hello,
When you have an inscribed quadrilateral, the opposite sides are supplementary.
So you can write and solve the following equation.
x + 6x + 19 = 180
7x + 19 = 180
7x = 161
x = 23
Now, plug in 23 for X and we will find the measurement of B.
6(23) + 19
138 + 19
157
The measure of angle B is 157 degrees. (The picture is not drawn to scale)
Good luck,
MrEQ
Y= 3x + 3. Use rise (how many it goes up or down) and divide it by run (how many it goes left or right) that number is your slope (aka M/ the number that goes with x. The number without the x attached is just where the line crosses the y axis
Answer:
See below:
Step-by-step explanation:
Hello! I hope you are having a nice day!
We can solve this problem in two steps; solving and theory.
I'll go and start off with the theory part!
Theory
We know that in geometry there are many types of triangles that have various different angles. With that, there are a few special triangles that people have made formulas for, one being a 30, 60, and 90 degree triangle.
The theorem states that the hypotenuse is
, the side opposite to 60 degrees is
, and the bottom is
.
Solving
We can solve this problem in a step, we just need to know what the theorem said and implement it here, since we know the values of the sides of the triangle, we can solve it by finding out the opposite side and applying the theorem rules.
If we look at the graph, we can see that the
part of the side opp. of 60 degrees is 4, that means that
would be double of 4, which is 8.
Therefore your answer would be: ![x=8](https://tex.z-dn.net/?f=x%3D8)
Cheers!
Answer:
Step-by-step explanation:
The goal to solving any equation is to have x = {something}. That means we need to get the x out from underneath that radical. It's a square root, so we can "undo" it by squaring. Square both sides because this is an equation. Squaring both sides gives you
![x^2=-3x+40](https://tex.z-dn.net/?f=x%5E2%3D-3x%2B40)
Get everything on one side of the equals sign and set the quadratic equal to 0:
![x^2+3x-40=0](https://tex.z-dn.net/?f=x%5E2%2B3x-40%3D0)
Throw this into the quadratic formula to get that the solutions are x = 5 and -8. We need to see if only one works, both work, or neither work in the original equation.
Does
?
and
![5=\sqrt{25}](https://tex.z-dn.net/?f=5%3D%5Csqrt%7B25%7D)
and 5 = 5. So 5 works. Let's try -8 now:
and
so
![-8=\sqrt{64}](https://tex.z-dn.net/?f=-8%3D%5Csqrt%7B64%7D)
-8 = 8? No it doesn't. So only 5 works. Your choice is the third one down.