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3 years ago

The length of the base of a rectangular prism 8 inches

Mathematics

1 answer:

madam [21]3 years ago

5 0

Answer:

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Step-by-step explanation:

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Find the perimeter.

likoan [24]

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3 years ago

A set of physics exam scores are normally distributed with a mean of 80 points and a standard deviation of 6

Anuta_ua [19.1K]

Answer:

The proportion of exam scores that are lower than Irina's score is 0.9938

Step-by-step explanation:

mean: 80 points

standard deviation (sd): 6 points
value of interest (x): 95 points

z-score is computed as follows:

z = (x - mean)/sd

z = (95 - 80)/6 = 2.5

We want to find:

P(z < 2.5)

From the table attached:

P(z < 2.5) = 0.9938

3 0

3 years ago

Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour

UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

$C(t) = C(0)e^{rt}$

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So $C(0) = 110$

Husband

Half life of 4 hours. So

$C(4) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{4r}$

$e^{4r} = 0.5$

Applying ln to both sides

$\ln{e^{4r}} = \ln{0.5}$

$4r = \ln{0.5}$

$r = \frac{\ln{0.5}}{4}$

$r = -0.1733$

So for the husband

$C(t) = 110e^{-0.1733t}$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.1733t}$

$C(11) = 110e^{-0.1733*11} = 16.35$

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

$C(10) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{10}$

$e^{10r} = 0.5$

Applying ln to both sides

$\ln{e^{10r}} = \ln{0.5}$

$10r = \ln{0.5}$

$r = \frac{\ln{0.5}}{10}$

$r = -0.0693$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.0693t}$

$C(11) = 110e^{-0.0693*11} = 51.33$

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0

3 years ago

Help please <br> Introduction to statistics: mastery test

Phantasy [73]

Answer:

Nonstatistical= HOW MANY ORANGES DID SALLY AT LAST MONTH, HOW MANY HOURS DID I SPEND ON EXTRA CIRICULA..., and HOW MANY DOGS DO I HAVE

Statistical: The other ones.

Step-by-step explanation: Please Tell me if it was Wrong.

4 0

3 years ago

AnsweR quickkkkkKkkkkkk

Papessa [141]

Answer:

A & E

Step-by-step explanation:

_________________

4 0

3 years ago