Let ABC be a triangle in the 3rd quadrant, right-angled at B.
So, AB-> Perpendicular BC -> Base AC -> Hypotenuse.
Given: sinθ=-3/5 cosecθ=-5/3
According to Pythagorean theorem, square of the hypotenuse is equal to the sum of square of the other two sides.
Therefore in triangle ABC, 〖AC〗^2=〖AB〗^2+〖BC〗^2 ------
--(1)
Since sinθ=Perpendicular/Hypotenuse ,
AC=5 and AB=3
Substituting these values in equation (1)
〖BC〗^2=〖AC〗^2-〖AB〗^2
〖BC〗^2=5^2-3^2
〖BC〗^2=25-9
〖BC〗^2=16
BC=4 units
Since the triangle is in the 3rd quadrant, all trigonometric ratios, except tan
and cot are negative.
So,cosθ=Base/Hypotenuse Cosθ=-4/5
secθ=Hypotnuse/Base secθ=-5/4
tanθ=Perpendicular/Base tanθ=3/4
cotθ=Base/Perpendicular cotθ=4/3
Answer:
Technically neither, but Mia is correct.
Step-by-step explanation:
Slope-Intercept Form: y = mx + b
Since our slope <em>m</em> is equal to 6, it is a positive number. That means that the slope/line will be positive, so the line should be going up, not down. That means the blue line would be correct. Therefore, Mia is correct.
Technicality:
Since the blue line is dotted, the equation should be a <em>inequality </em>and not a linear equation. No solutions on the line would technically work. If the equation was y < 6x + 4 or something with an inequality sign, then it would be correct.
Answer:
160°
Step-by-step explanation:
-Given the angle in radians as 
-We know that 
-Let our angle theta be X
#We therefore equate and cross multiply:
Hence, angle θ is 160°
Answer:
x = 98
Step-by-step explanation:
The sum of the interior angles in a polygon is
sum = 180° (n - 2) ← n is the number of sides
here n = 7, thus
sum = 180° × 5 = 900°
Sum the interior angles and equate to 900
x + 146 + 122 + 142 + 140 + 110 + 142 = 900, that is
x + 802 = 900 ( subtract 802 from both sides )
x = 98
Step-by-step explanation:
