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3 years ago

What gas made up the largest portion of earth's atmosphere for most of earth's history

1 answer:

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Gases in Earth's Atmosphere. Nitrogen and Oxygen are by far the most common. Dry air is composed of about 78% Nitrogen (N2) and about 21% Oxygen (O2). Argon, Carbon Dioxide (CO2), and many other gases are also present in much lower amounts; each makes up less than 1% of the atmosphere's mixture of gases.

So therefore Oxygen is the gas that makes up the largest portion of the Earths Atmosphere.

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Why is absolute dating more accurate than relative dating?

nadezda [96]

Absolute dating uses the half-life of an element.

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3 years ago

Each of the four pedigrees that follow represents a human family within which a genetic disease is segregating. Affected individ

Ne4ueva [31]

Answer:

The following four traits are -:

Pedigree 1 - A recessive trait (autosomal recessive) is expressed by pedigree 1.
Pedigree 2- Recessive inheritance is defined by Pedigree 2.
Pedigree 3 - The inheritance of the dominant trait (autosomal dominant) is illustrated by Pedigree 3.
Pedigree 4- An X-like dominant trait is expressed by Pedigree 4.

Explanation:

Explaination of each pedigree chart-

Pedigree 1 demonstrates the recessive trait since their children have been affected by two unaffected individuals. If the characteristics were X-linked, in order to have an affected daughter, I-1 would have to be affected. $X^A$ In this, both parents are autosomal recessive trait carriers, so the child will be affected by a 1/4 (aa)
Recessive inheritance is defined by Pedigree 2. This is X-related inheritance as autosomal recessive inheritance has already been accounted for in part 1. This inference is confirmed by evidence showing that the father (I-1) is unaffected and that only the sons exhibit the characteristic in generation II, suggesting that the mother must be the carrier. The individual I-2 is a carrier for this X-linked trait. A typical Xa chromosome is attached to the unaffected father (I-1), so the chance of carrier II-5 is 1/2. Probability of an affected son = 1/2 (probability II-5 is a carrier) x 1/2 (probability II -5 contributes ( $X^A$ ) x 1/2 (probability of Y from father II-6) = 1/8. An affected daughter's likelihood is 0 because a typical $X^A$ must be contributed by II-6.
The inheritance of the dominant trait is demonstrated by Pedigree 3 because affected children still have affected parents (remember that all four diseases are rare). The trait must be autosomal dominant because it is passed down to the son by the affected father. There is a 1/2 risk that the heterozygous mother (II-5) would pass on mutant alleles to a child of either sex for an autosomal dominant feature.
Pedigree 4 is an X-linked dominant function characterized by the transmission to all of his daughters from the affected father but none of his son. On the mutant X chromosome, the father (I-1) passes on to all his daughters and none of his sons. As seen by his normal phenotype, II-6 therefore does not bear the mutation. An affected child's likelihood is 0.

In the question the pedigree chart was missing ,hence it is given below.

7 0

3 years ago

What organisms can live where nothing else lives?

tatyana61 [14]

Archea is the correct answer. :) good luck!

3 0

3 years ago

Read 2 more answers

Toward an Artificial Cell Scientists have recently constructed an artificial ribosome in vitro from purified ribosomal proteins

dalvyx [7]

Answer:

RNAs and proteins can bind via electrostatic interactions, hydrophobic interactions, Hydrogen bonding interactions and base stacking interactions

Explanation:

Proteins bind to nucleic acids (i.e., both DNA and RNA) through different types of interactions:

- electrostatic interactions, also known as van der Waals interactions, refer to attractive/repulsive interactions between molecules depending on their electric charges.

- hydrophobic interactions, i.e., interactions between nonpolar molecules and water molecules

- Hydrogen bonding interactions resulting from the interaction between a hydrogen (H) atom that bind to an electronegative atom (e.g., N, O, F, etc), and another electronegative atom.

- base stacking interactions that result from the arrangement of RNA nucleotides

In this case, it is also important to highlight that the interaction will depend on the specific tertiary structure of ribosomal proteins and ribosomal RNAs (rRNAs).

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3 years ago

Babies with very low or very high birth weight are less likely to survive. The graph shows the percentage of babies born at

dalvyx [7]

Answer:

Option C is correct.

The information provided clearly shows that the babies with average weights form a stable selection, the average is favoured.

Stabilizing selection is occurring because the average is favored.

Explanation:

Concluding Part of the question

A graph entitled Percentage of Babies born at Different Weights has weight in pounds on the horizontal axis, and percentage on the vertical axis. A small percentage of babies are born at the low and higher birth weights, and a greater amount are around 7 to 8 pounds.

Which statement is a valid claim that could be made using the data in the graph?

A) Directional selection is occurring because the graph favors an extreme.

B) Disruptive selection is occurring because the two extremes are favored.

C) Stabilizing selection is occurring because the average is favored.

D) Biodiversity variation is occurring because there is an increase in trait variation.

Explanation

Stabilizing selection represents a form of natural selection where the intermediate variants of a trait, that is the non-extreme trait values are the ones that ensure the survival and subsequent formation of stable population of the species with this average traits.

In this question, it is given through the data from the graph that babies with very low or very high weights are less likely to survive.

And it is logical as very low weight babies are most likely to be very weak, fragile and susceptible to being on the wrong side of natural selection and very high weight babies have all sorts of overweight issues plus the fact that they have to literally be squeezed out of the womb through a very narrow canal, really pushing their oversight bodies to its limits very early making them also susceptible to being on the wrong side of natural selection.

The average weight babies on the other hand do not experience any of the issues discussed in the last paragraph, they are usually healthy and thus have a high survival rate. So, it is evident to see that the population of babies stabilizes based on a particular non-extreme trait value (baby weight) through stabilizing selection.

Hope this Helps!!!

8 0

3 years ago