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Mazyrski [523]
3 years ago
12

Faith scored -1 in golf while Joy scored a -15. Which golfer scored further under

Mathematics
1 answer:
gayaneshka [121]3 years ago
5 0
I think the answer is Joy
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Solve x/10 = –7.<br><br> A. x = –0.7<br> B. x= –17<br> C. x = –70<br> D. x = 3
konstantin123 [22]
\frac{x}{10} = -7   Multiply both sides by 10
x = -70

C. x = -70
4 0
3 years ago
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Decrease 1280 by 67%
blondinia [14]
67% of 1280 is 857.6 substrack it and it's = 422.4
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4 years ago
WILL MARK BRAINLIEST!
Artist 52 [7]

Answer:

Following are the responses to the given points:

Step-by-step explanation:

Dilation implies the triangle \Delta XYZ stretched through the factor "2".  

m\angle Y = m\angle C = 90^{\circ} \leftarrow given \\\\  

right triangles:

\Delta  XYZ and \Delta  ACB \\\\\angle X \cong \angle A \leftarrow given\\\\

complementary angles:  

\angle X \ and\  \angle Z

m\angle Z = 90^{\circ} - m\angle X \\\\

complementary angles:

\angle A \ and\  \angle B

m\angle B = 90^{\circ} - m\angle A \\\\\therefore \\\\ \angle Z \cong \angle B \\\\\Delta  XYZ \sim  \Delta ACB \\\\

Same triangles: proportional side are corresponding, congruence angles are respective.

\sin \angle X = \frac{5}{5.59} \leftarrow given \\\\\sin\angle X = \frac{YZ}{XY} \\\\YZ = 5 (units) \rightarrow leg in \Delta XYZ \\\\XZ = 5.59 (units) \rightarrow hypotenuse \ in\  \Delta XYZ\\\\

Calculating the length of leg XY:

XY = \sqrt{((5.59)^2 - 52)} \cong 2.4996 (units)\\\\\frac{CB}{YZ} = 2 \leftarrow given \\\\CD = 2YZ = 2 \times 5 = 10 \ (units)\\\\\frac{AC}{XY} = 2 \leftarrow  \ given\\\\AC = 2XY \cong 2 \times  2.4996 \cong 4.999\  (units)\\\\

3 0
3 years ago
Six over n equals twenty-one over twenty-eight<br> A. 13<br> B. 9<br> C. 8<br> D. 15
podryga [215]
C. Or 8, trust!!!!!!!!!
3 0
3 years ago
A local high school has both male and female students.
Kitty [74]

Answer:

a. P(male) = 0.4

b. P(no sport and male) = 0.1

c. Unclear question (isn't it the same as b.?)

Step-by-step explanation:

The data below is what I've worked according to, which isn't very clear from the question so the answers are only correct if this is the correct table of data;

\left[\begin{array}{ccc}&No \ Sports&Sports\\Female&10&32\\Male&7&21\end {array}\right]

a.

P(male) = \frac{7 + 21}{70} \\\\ = \frac{28}{70} \\\\ = \frac{2}{5}

b.

Using the tree diagram in the picture;

P(no \ sport \ and \ male) = \frac{2}{5} * \frac{1}{4} \\\\ = \frac{1}{10}

8 0
2 years ago
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