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iVinArrow [24]
3 years ago
10

If [x] denotes the least integer greater than or equal to x and [x/2] = 0, which of the following could be the value of x?A. -2B

. -3/2C. 1/2D. 1E. 2
Mathematics
1 answer:
podryga [215]3 years ago
3 0

Answer:

B) -3/2

Step-by-step explanation:

If [x/2]=0 then x/2 is a number such that the least integer greater than or equal to x/2 is 0. We can rewrite this as the inequality x/2≤0. Then, the value of x in C, D and E is wrong because they are positive numbers, then x/2 would be a positive number which contradicts this inequality.

Now, 0 is the least integer that satisfies this inequality, therefore we cannot have that x/2≤-1 since -1 is an integer and -1<0. Then x/2>-1. This discards A as wrong, because for x=-2, x/2=-1, contrary to x/2>-1.

Thus B is the right answer. To verify, if x=-3/2, then x/2=-3/4 and we have that -1<-3/4≤0 as required.

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Help.........................<br><br>​
garri49 [273]
<h3>Answer: Choice A</h3>

x^2\left(\sqrt[4]{x^2}\right)

=====================================================

Explanation:

The fourth root of x is the same as x^(1/4)

I.e,

\sqrt[4]{x} = x^{1/4}

The same applies to x^10 as well

\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4}

Multiply the exponents 10 and 1/4 to get 10/4

\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4} = x^{10*1/4} = x^{10/4}

\sqrt[4]{x^{10}} = x^{10/4}

-----------------------

If we have an expression in the form x^(m/n), with m > n, then we can simplify it into an equivalent form as shown below

x^{m/n} = x^a\sqrt[n]{x^b}

The 'a' and 'b' are found through dividing m/n

m/n = a remainder b

'a' is the quotient, b is the remainder

-----------------------

The general formula can easily be confusing, so let's replace m and n with the proper numbers. In this case, m = 10 and n = 4

m/n = 10/4 = 2 remainder 2

We have a = 2 and b = 2

So

x^{m/n} = x^a\sqrt[n]{x^b}

turns into

x^{10/4} = x^2\sqrt[4]{x^2}

which means

\sqrt[4]{x^{10}} = {x^2} \sqrt[4]{x^2}

7 0
3 years ago
Given the graph of a line y=−x. Write an equation of a line (there are many) which intersects the line, but is not perpendicular
BaLLatris [955]
This would be any equation whose slope isn’t -1 or 1.

If the slope was -1, the lines would be parallel because the have the same slope.

If the slope was 1, the lines would be perpendicular because 1 is the negative reciprocal of -1.

Any line with any other slope will intersect with y=-x.

Hope this helps!
5 0
3 years ago
Also how would you round 2.59 to the nearest tenths ?
Maslowich

Answer:

<em>2.6</em>

Step-by-step explanation:

The tenths digit is the 5.

Drop every digit after the 5. You get 2.5

Now you need to see if the 5 stays as it is or if it goes up by 1 to 6.

The first digit after the 5 you dropped is 9. Since 9 is greater than 4, the previous digit goes up by 1, so the 5 becomes a 6.

The final answer is 2.6

5 0
3 years ago
Read 2 more answers
The price of a fan is $15. The price is 27% lower than last week.
liraira [26]
Comes down to exactly 10.95
7 0
4 years ago
1.43 x 10*9 in standard form
QveST [7]
The exponent is 9, making it 10 to the power of 9. As the exponent is positive, the solution is a number greater than the origin or base number.
3 0
3 years ago
Read 2 more answers
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