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dexar [7]
3 years ago
7

Jamie picks out of blouse to purchase. it is on sale for 25% off plus she has a $10 off coupon. she pays $23 for the blouse. det

ermine the original price​
Mathematics
1 answer:
Anna007 [38]3 years ago
8 0

Answer:

It originally costs $44

Step-by-step explanation:

To find the original price, first we add the $10 back on to the price.

$23 + $10 = $33

Now that we have this, we need to find out how much it was before the markdown. Since she paid 75% of the original price (25% less than the original), we can divide by that percentage.

$33/75% = $44

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Kitty [74]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
Consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number,
Aleksandr-060686 [28]

Answer:

The expected value of the points earned on a single roll in this game is \dfrac{1}{6} = 0.1667 .

Step-by-step explanation:

We are given that consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number, that many points will be added to the player’s total. Any other roll will be deducted from the player’s total.

Assuming that the numbered cube is a dice with numbers (1, 2, 3, 4, 5, and 6).

Here, the prime numbers are = 1, 2, 3 and 5

Numbers which are not prime = 4 and 6

This means that if the dice got the number 1, 2, 3 or 5, then that many points will be added to the player’s total and if the dice got the number 4 or 6, then that many points will get deducted from the player’s total.

Here, we have to make a probability distribution to find the expected value of the points earned on a single roll in this game.

Note that the probability of getting any of the specific number on the dice is   \dfrac{1}{6} .

      Numbers on the dice (X)                       P(X)

                      +1                                                 \frac{1}{6}

                      +2                                                \frac{1}{6}

                      +3                                                \frac{1}{6}

                      -4                                                 \frac{1}{6}

                      +5                                                \frac{1}{6}

                      -6                                                 \frac{1}{6}

Here (+) sign represent the addition in the player's total and (-) sign represents the deduction in the player's total.

Now, the expected value of X, E(X)  =  \sum X \times P(X)

   =  (+1) \times \frac{1}{6} +(+2) \times \frac{1}{6} +(+3) \times \frac{1}{6} +(-4) \times \frac{1}{6} +(+5) \times \frac{1}{6} +(-6) \times \frac{1}{6}

   =  \frac{1}{6} + \frac{2}{6} + \frac{3}{6} - \frac{4}{6} + \frac{5}{6} - \frac{6}{6}

   =  \frac{1+2+3-4+5-6}{6}

   =  \frac{11-10}{6}= \frac{1}{6}

Hence, the expected value of the points earned on a single roll in this game is  \frac{1}{6} = 0.1667 .

4 0
4 years ago
PLZZZZZ HELP AND HURRRRRY!
galben [10]

Answer:

b

Step-by-step explanation:

4 0
3 years ago
Hannah is at the supermarket to buy carrots and potatoes. If she buys 2 pounds of carrots and 3 pounds of potatoes, it will cost
zhenek [66]

Answer:

Carrots cost $ 1.75 a pound which is more than potatoes cost.

Step-by-step explanation:

Let,

Carrots cost $ x per pound and potatoes cost $ y per pound.

Buying 2 pounds of carrots  and 3 pounds of potatoes will cost her

$ (2\times x + 3\times y)

and

Buying 4 pounds of carrots and 4 pounds of potatoes will cost her

$ (4\times x + 4\times y)

According to the question,

(2\times x + 3\times y) = 8-----(1)

(4\times x + 4\times y) = 13-----(2)

multiplying (1) by 2 we get,

(4\times x + 6\times y) = 16-----(3)

Deducting (2) from (3) we get,

2\times y = 3

⇒ y = \frac{3}{2} = 1.5------------------(4)

Putting value of y in (1) we get,

(2\times x = 8 - 3\times 1.5) = 3.5

⇒  x =\frac{3.5}{2} = 1.75 ------------(5)

8 0
4 years ago
Help me pls I need help right now
kolbaska11 [484]

Answer:

The Volume is 72 cm^3.

Step-by-step explanation:

6 0
3 years ago
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