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Dimas [21]
3 years ago
11

Emily and Molly are selling pies for a school fundraiser. Customers can buy cherry pies and lemon pies. Emily sold 4 cherry pies

and 1 lemon pie for a total of $30. Molly sold 8 cherry pies and 6 lemon pies for a total of $100. What is the cost for one CHERRY and LEMON pie.
Mathematics
1 answer:
dmitriy555 [2]3 years ago
5 0

Answer:

<h2>cherry pie = 5</h2><h2>lemon pie =10</h2>

Step-by-step explanation:

Step one:

let cherry be x

and lemon be y

the systems of the equation for the solution is given as

4x+y=30-----------1

8x+6y=100------2

Step two:

solve the equation simultaneously by substitution we have

4x+y=30

y=30-4x

put y=30-4x in equation 2

8x+6(30-4x)=100

8x+180-24x=100

8x-24x=100-180

-16x=-80

x=80/16

x=5

put x=4 in y=30-4x

y=30-4(5)

y=30-20

y=10

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The answer would be B) 6x + 2.

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3 years ago
5+2 times 2 (12 divided by 3)
OLEGan [10]

Answer:

56

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
6(m + 2 + 7m)
Inga [223]

Part A: 6 ( 8m + 2) and 48m + 12

Part B: 48m - 48m = 12 - 12

Part C: 6 (10) = 6(10)

<h3>How to determine the expressions</h3>

1. The two expressions could be gotten thus;

6(m + 2 + 7m)

Collect like terms in the bracket

6 ( 8m + 2) ⇒ first expression

6(m + 2 + 7m)

Expand the bracket

6m + 12 + 42m

Collect like terms

6m + 42m + 12

48m + 12 ⇒ second expression

Part B:

6(m + 2 + 7m) = 48m + 2

Expand the bracket

6m + 12 + 42m = 48m + 2

Collect like terms

48m - 48m = 12 - 12

0 = 0

Part C:

Let the expression from A be 6 ( 8m + 2)

6(m + 2 + 7m) = 6 ( 8m + 2)

Let the number be m = 1

Substitute the values

6(1 + 2 + 7(1) ) = 6 (8(1) + 2)

6 ( 1 + 2 + 7) = 6 (10)

6 (10) = 6(10)

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