write two division problems related to the multiplication problem below. 8×(-2)=-16
1 answer:
We can write two division problems related the given equation as follows.
Division problem one :
Here 8 is in multiplication with -2 on the left side.
so when we bring this 8 on the right side, we will have to apply opposite operation of multiplication which is division.
so dividing (-16) by 8 on the right side, we have:
Division problem two :
Here -2 is in multiplication with 8 on the left side.
so when we bring this (-2) on the right side, we will have to apply opposite operation of multiplication which is division.
so dividing (-16) by (-2) on the right side, we have:
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The isosceles triangle is proved below.
<h3>How to illustrate the triangle?</h3>The complete information wasn't found. The proofing of the triangle will be illustrated. It should be noted that the angles opposite to the equal sides of an isosceles triangle are also equal.
Proof: Consider an isosceles triangle ABC where AC = BC.
We need to prove that the angles opposite to the sides AC and BC are equal, that is, ∠CAB = ∠CBA.
We first draw a bisector of ∠ACB and name it as CD.
Now in ∆ACD and ∆BCD we have,
AC = BC (Given)
∠ACD = ∠BCD (By construction)
CD = CD (Common to both)
Thus, ∆ACD ≅∆BCD (By SAS congruence criterion)
So, ∠CAB = ∠CBA (By CPCT)
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