Answer:
10
30%
Step-by-step explanation:
In this case it would be the combination of 2 taken from 5.
That is, when n = 5 and r = 2
nCr = n! / r! * (n-r)!
replacing
5C2 = 5! / (2! * 3!)
5C2 = 10
Which means that the sample space is 10 possible combinations.
the probability that the card you draw is even is 3/5, since there are 3 even cards that exist and 5 is the total number of cards.
Now, so that both are for it would be the multiplication of the previous probability and 2/4 because an even card and a card in general have already been drawn:
(3/5) * (2/4) = 0.3
So the probability that both are even is 30%
