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3 years ago

7

In 2012, the population of China was about 1.351 x 10^9 and the population of Japan was about 1.280 x 10^8. Based upon these est

imates, approximately how many more people lived in China than in Japan in 2012?

1 answer:

Brilliant_brown [7]3 years ago

5 0

Answer:

7 x10^6

Step-by-step explanation:

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A politician claims that a proposal for a new traffic law is broadly supported by both political parties and that a person from

Mashutka [201]

Answer:

Based on the 95% confidence interval for the difference in population proportion, there is convincing statistical evidence that he is correct

Step-by-step explanation:

The proportion from the sample of people from his party that support the law = 70%

The number the members of the politicians political party that support the law = 550 people

The proportion from the sample of people from the other party that support the law = 65%

The number the members of the politicians political party that support the law = 420 people

The confidence level of the test = 95%

The given confidence interval for the difference in proportion, C.I. = (-0.010, 0.110)

Given that the 95% confidence interval for the difference in population proportion ranges from -0.010, to 0.110, it is 95% certain that 0 is among the likely difference in proportion between the two populations and therefore, there is sufficient statistical evidence to suggest that there is no difference in the proportion of the members of either political that support the proposed new traffic law.

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What issue did the great compromise resolve

kondor19780726 [428]

Answer:

The issue of the great compromise resolved representation.

Step-by-step explanation:

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4 years ago

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Answer:

Step-by-step explanation:

option 2

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3 years ago

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Which two numbers on the number line has an absolute value of 3?

Darya [45]

3 and -3

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3 years ago

Step by step 7 ,9, and 11 please. EVEN IF U CANT DO ALL, u can help with 1 or 2. Ill mark brainly.

gregori [183]

Answer:

7) $4 \ log_3(x) - 4 \ log_3(y)$

9) $5log_4(7) - 5log_4(12)$

11) $5log_5 \ (x) - log_5 \ (y)$

Step-by-step explanation:

$log_3 (\frac{x}{y})^{4}$

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Use Logarithm of a Quotient which states

$log_b \frac{M}{N} = log_b M-log_bN$

And also use Logarithm of a Power which states

$log_b\ M^{n} = n\log_bM$

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So using these two properties,

7. $4 \ log_3(x) - 4 \ log_3(y)$

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For #9, use the same logarithm propertied

$log_4(\frac{7}{12})^5 = 5log_4(7) - 5log_4(12)$

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#11 is also the same concept

$log_5\ \frac{x^5}{y} = 5log_5 \ (x) - log_5 \ (y)$

It is not - 5 log5(y) since only x is to the power of 5 not y

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Hope this is what you were looking for and helps you! Have a nice day/night :)

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3 years ago