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Softa [21]
3 years ago
5

In what order would we solve for n? 3n - 4 = 14

Mathematics
1 answer:
Blizzard [7]3 years ago
3 0
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation;

3*n-4-(14)=0

Pull out like factors :

3n - 18 = 3 • (n - 6)

Solve : 3 = 0

This equation has no solution.
A a non-zero constant never equals zero.

Solve : n-6 = 0

Add 6 to both sides of the equation :
n = 6
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If a polynomial function f(x) has roots –8, 1, and 6i, what must also be a root of f(x)? A. –6
anyanavicka [17]

Answer:

-6i

Step-by-step explanation:

Complex roots always come in pairs, and those pairs are made up of a positive and a negative version. If 6i is a root, then its negative value, -6i, is also a root.

If you want to know the reasoning, it's along these lines: to even get a complex/imaginary root, we take the square root of a negative value. When you take the square root of any value, your answer is always "plus or minus" whatever the value is. The same thing holds for complex roots. In this case, the polynomial function likely factored to f(x) = (x+8)(x-1)(x^2+36). To solve that equation, you set every factor equal to zero and solve for the x's.

x + 8 = 0

x = -8

x - 1 = 0

x = 1

x^2 + 36 = 0

x^2 = -36 ... take the square root of both sides to get x alone

x = √-36 ... square root of an imaginary number produces the usual square root and an "i"

x = ±6i

6 0
3 years ago
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snow_tiger [21]

Answer:

It is equivalent to a decimal that does not terminate.

Step-by-step explanation:

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4 0
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You should search it on youtube becouse pepople cant really explain or draw the shape to show you
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algol13

Answer:

+5.5

Step-by-step explanation:

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Step-by-step explanation:

one of you answer this question

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