B=number of ticets sold before
a=number of tickets sold after
cost of a ticket=number of tickets times cost per ticket
beforecost=39.95b
aftercost=54.95a
total cost=925000
39.95b+54.95a=925000
total number tickets=20000
b+a=20000
we have
39.95b+54.95a=925000
b+a=20000
multiply second equation by -39.95 and add to first equatin
39.95b+54.95a=925000
<u>-39.95b-39.95a=-799000 +</u>
0b+15a=126000
15a=126000
divide bot sides by 15
a=8400
sub back
b+a=20000
b+8400=20000
minus 8400 both sides
b=11600
11,600 tickets sold before
8400 tickets sold after
Answer:
1) 5 2) the first one
Step-by-step explanation:
1)
since the first time multiplying 8 to get a two digit number ending in zero is forty, i multiplied both by 5
2) 8 times 12= 96+20=116
10 times 12=120 (already too much)+10=130
i hope this helps u
pls give a brainliest (i only need one more!) and a thx
Answer:
veinte
Step-by-step explanation:
Son veinte porque si alineas 10 + 10 así-
10
+ 10, solo agregas las que serán un dos. Luego sueltas el cero, que será 20.
15!!! is the answer to your question:)
