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3 years ago

Jonas is the 4/9 of the chapters of life do you agree if not what mistake did she make and why

Mathematics

1 answer:

Naya [18.7K]3 years ago

4 0

Answer:

yes i do agree because 4/9 is over the 50% mark so it is a yes she did make it over most of the chapters of life

Step-by-step explanation:

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There were some people on a train. 19 people got off the train at the first stop. 17 people get on the train. Now there is 63 pe

maria [59]

Answer:

65 people.

Step-by-step explanation:

We have to work backwards.

We end with 63 people, and at the stop we lost 19 people and gained 17.

$x - 19 + 17 = 63\\$ ; if x = # people at the beginning

$x - 19 + 17 = 63\\x - 2 = 63\\x = 65$

There were 65 people on the train to begin with.

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Simplify X+^2+8x+7/X^2-1

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Step-by-step explanation:

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2 years ago

If an instrument measures in units of 1 then any value between which two values would be measure as 5?

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2 years ago

In a direct variation equation, f(x)=6 when x = 4. What is the direct variation equation?

jeyben [28]

Answer:

$f(x) = \dfrac{3}{2}x$

Step-by-step explanation:

The general direct variation equation is

y = kx

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3 years ago

Find the derivative of the following. please show the steps when you answer :1) f(x) = 8xe^x2) y= 5xe^x^43) f(x)= x^8+5/x4) f(t)

borishaifa [10]

Answer:

Since,

$\frac{d}{dx}x^n = nx^{n-1}$

$\frac{d}{dx}(f(x).g(x)) = f(x).\frac{d}{dx}(g(x)) + g(x).\frac{d}{dx}(f(x))$

$\frac{d}{dx}(\frac{f(x)}{g(x)})=\frac{g(x).f'(x) - f(x) g'(x)}{(g(x))^2}$

1) $y = 8x e^x$

Differentiating with respect to x,

$\frac{dy}{dx}=8( x \times e^x + e^x) = 8(xe^x + e^x) = 8e^x(x+1)$

2) $y = 5x e^{x^4}$

Differentiating w. r. t x,

$\frac{dy}{dx}=5(x\times 4x^3 e^{x^4}+e^{x^4})=5e^{x^4}(4x^4+1)$

3) $y = x^8 + \frac{5}{x^4}$

Differentiating w. r. t. x,

$\frac{dy}{dx}=8x^7 - \frac{5}{x^5}\times 4 = 8x^7 - \frac{20}{x^5}=\frac{8x^{12}-20}{x^5}$

4) $f(t) = te^{11}-6t^5$

Differentiating w. r. t. t,

$f'(t) = e^{11} - 30t^4$

5) $g(p) = p\ln(2p+3)$

Differentiating w. r. t. p,

$g'(p) = p\frac{1}{2p+3}(2) + \ln(2p+3) = \frac{2p}{2p+3}+\ln(2p+3)$

6) $z = (te^{6t}+e^{5t})^7$

Differentiating w. r. t. t,

$\frac{dz}{dt}=7(te^{6t}+e^{5t})^6 ( 6te^{6t}+e^{6t} + 5e^{5t})$

7) $w =\frac{2y + y^2}{7+y}$

Differentiating w. r. t. y,

$\frac{dw}{dy} = \frac{(7+y)(2+2y)-(2y+y^2)}{(7+y)^2} = \frac{14 + 2y + 14y +2y^2 - 2y - y^2}{(7+y)^2}=\frac{14+14y+y^2}{(7+y)^2}$

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3 years ago