<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
$124.00 (36ft of fencingx1.50=$54)(area 80 ft/4=20 bagsx 3.50 = $70) 54 + 70 = $124.00
Answer:
1 to 3
Step-by-step explanation:
3 blue: 9 yellow
Divide each side by 3
3/3 : 9/3
1 blue: 3 yellow
1 to 3
The anwser to your problem is 1,800
Answer:
B
Step-by-step explanation: