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<u>QUESTION 1</u>
In figure A, the area of the bigger square is . This means that the length of this square is the hypotenuse of the right angle triangle formed, which is
.
The area of the two smaller squares are and
.
The length of these two squares form the two shorter legs of the right angle triangle, which are and
units respectively.
Therefore we can write the equation, .
This implies that,
We can see that the sum of the squares of the two shorter legs equals the square of the longer side which is the hypotenuse and this what the Pythagoras theorem says.
But in fig. B,
Therefore the correct answer is Fig A.
<u>QUESTION 2</u>
See diagram.
We introduce the two lines as shown in the diagram.
From Pythagoras' Theorem,
But units.
and
units.
This implies that,
to the nearest tenth.
<u>QUESTION 3</u>
The numbers and
form a Pythagorean triplet because
.
If these numbers represent the side lengths of a triangular fence, then the triangular fence must be a right angle triangle.
The correct answer is B
Yes,because .
<u>QUESTION 4</u>
See graph.
We want to find the image of the triangle with vertices A(-5,-4), B(-2,-4), and C(-5,-1) after a reflection in the x-axis.
The mapping for this transformation is
.
We just have to negate the y-coordinates.
.
.
.
Answer:
<h3>Explanation:
1.) Rewrite √24 = Rewrite √54 =
Divide both terms by the denominator; √6 cancels. 2-3 = -1
2.) Rewrite as ×
The 3's cancel. 10/2 = 5√2 in the numerator.
√5 × √5 = 5 in the denominator. The 5's cancel.
That leaves √2 ≈1.4142
3.) Divide the terms in the numerator by the term in the denominator.
√2's cancel. 10π/2 = 5π 8π/2 = 4π
Subtract and we are left with π = 3.14159
4.) The square roots are reciprocals. They multiply to 1
We are left with π × π = π² ≈ 9.8696
<h3> </h3>