The perimeter of a square is the sum of its sides and they
are all equal, so to obtain the length of each of them we divide the perimeter
of the first fence between 4:
P1= 64 feet/4 sides
P1= 16 feet
Then, the length of each side of the second fence will
increase 2 feet at each end, as shown in the figure. We have then that the
perimeter of the second fence is:
P2 = 20 feet x 4 sides
P2 = 80 feet
The sum of the perimeters of both fences is:
PT = P1 + P2
PT = 64 feet + 80 feet
PT = 144 feet
Total cost = 1.17 $ x 144 feet
Total cost = 168.48 $
The total cost of the fences was $ 168.48
Answers:
- a) x = 9
- b) arc JK = 68
- c) arc MJ = 112
- d) arc LMK = 248
================================
Explanation:
Arcs JK and KL form a semicircle, so they add to 180 degrees
(arcJK) + (arcKL) = 180
(5x+23) + (17x-41) = 180
22x-18 = 180
22x = 180+18
22x = 198
x = 198/22
x = 9
Then you'll use this x value to find arc JK and arc KL
arc JK = 5x+23 = 5*9+23 = 68
arc KL = 17x - 41 = 17*9-41 = 112
Since central angles MNJ and KNL are vertical angles, this means minor arcs MJ and KL are congruent arcs. So arc MJ is also 112 degrees
Arc LMK is basically nearly everything of the full circle, but we exclude out the portion from L to K (the shorter distance)
arc LMK = (full circle) - (measure of minor arc LK)
arc LMK = 360 - 112
arc LMK = 248
Answer:
D
Step-by-step explanation:
Check the picture below.
let's recall that a kite is a quadrilateral, and thus is a polygon with 4 sides
sum of all interior angles in a polygon
180(n - 2) n = number of sides
so for a quadrilateral that'd be 180( 4 - 2 ) = 360, thus
![\bf 3b+70+50+3b=360\implies 6b+120=360\implies 6b=240 \\\\\\ b=\cfrac{240}{6}\implies b=40 \\\\[-0.35em] ~\dotfill\\\\ \overline{XY}=\overline{YZ}\implies 3a-5=a+11\implies 2a-5=11 \\\\\\ 2a=16\implies a=\cfrac{16}{2}\implies a=8](https://tex.z-dn.net/?f=%5Cbf%203b%2B70%2B50%2B3b%3D360%5Cimplies%206b%2B120%3D360%5Cimplies%206b%3D240%20%5C%5C%5C%5C%5C%5C%20b%3D%5Ccfrac%7B240%7D%7B6%7D%5Cimplies%20b%3D40%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Coverline%7BXY%7D%3D%5Coverline%7BYZ%7D%5Cimplies%203a-5%3Da%2B11%5Cimplies%202a-5%3D11%20%5C%5C%5C%5C%5C%5C%202a%3D16%5Cimplies%20a%3D%5Ccfrac%7B16%7D%7B2%7D%5Cimplies%20a%3D8)