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grandymaker [24]
3 years ago
5

ANSWER ASAP GIVING BRAILIEST AND STUFF!

Mathematics
1 answer:
natita [175]3 years ago
6 0

Answer:

24s^2, 54s^2, 96s^2

Step-by-step explanation:

Let s represent the initial side length of the cube.  Then the area of each face of the cube is A = 6s^2 (recalling that the area of a square of side length s is s^2).

a) Now suppose we double the side length.  The total area of the 6 faces of the cube will now be A = 6(2s)^2, or 24s^2 (a 24 times larger surface area),

b) tripled:  A = 6(3s)^2 = 54x^2

c) quadrupled?  A = 6(4s)^2 = 96s^2

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A survey found that​ women's heights are normally distributed with mean 63.7 . And standard deviation 3.7 . The survey also foun
san4es73 [151]

Complete question :

A survey found that women's heights are normally distributed with mean 63.6 in and standard deviation 3.7 in. The survey also found that men's heights are normally distributed with mean 69.3 in and standard deviation 3.7 in. Consider an executive jet that seats six with a doorway height of 55.7 in.

1-What percentage of adult men can fit through the door without bending?

2-) Does the door design with a height of 56.35in. appear to be adequate? Why didn't the engineers design a larger door? Choose answer below

A. The door design is inadequate, because every person needs to be able to get into the aircraft without bending. There is no reason why this should not be implemented.

B. The door design is adequate, because the majority of people will be able to fit without bending. Thus, a larger door is not needed.

C. The door design is inadequate, but because the jet is relatively small and seats only six people, a much higher door would require major changes in the design and cost of the jet, making a larger height not practical.

D. The door design is adequate, because although many men will not be able to fit without bending, most women will be able to fit without bending. Thus, a larger door is not needed.

Answer:

A.) 0.135%

B.) C. The door design is inadequate, but because the jet is relatively small and seats only six people, a much higher door would require major changes in the design and cost of the jet, making a larger height not practical.

C.)

Step-by-step explanation:

Percentage of adult men that can fit the door without bending :

Obtain the Zscore :

Mean height of men, m = 67.5

Standard deviation, s = 3.7

Zscore = (x - m) / s ; where x = 56.4

Zscore = (56.4 - 67.5) / 3.7

Zscore = - 11.1 / 3.7

Zscore = - 3

P(Z < - 3) = 0.0013499 (Z probability calculator)

P(Z < - 3) = 0.0013499 * 100% = 0.13499%

8 0
3 years ago
Need a answer quick please help!
bija089 [108]
The answer would be choice a they are both functions
3 0
3 years ago
Read 2 more answers
1. A windshield wiper blade is 18 in Long. Calculate the area covered by the blade as it rotates through an angle of 122 degrees
sveta [45]

1. Area of a circle is pi x R^2

Area = 3.14 x 18^2

Area = 3.14 x 324= 1017.36 sq. In.

The blade covers 122 out of 360 degrees.

1017.36 x 122/360 = 345 square inches.

2.

Like above.

Area =3.14 x 75^2 = 17,662.5 square feet

17662.5 x 80/360 = 3,925 square feet.

4 0
3 years ago
On a cold day, hailstones fall with a velocity of 2i − 6k m s−1 . If a cyclist travels through the hail at 10i m s−1 , what is t
Paraphin [41]

Answer:

The velocity of the hail relative to the cyclist is V_{hc}=-8\hat{i}-6\hat{k}

The angle at which hailstones falling relative to the cyclist is \theta = 36.86^\circ

Step-by-step explanation:

Given : On a cold day, hailstones fall with a velocity of 2\hat{i}-6\hat{k}\text{ m/s} . If a cyclist travels through the hail at 10\hat{i} \text{ m/s}.

To find : What is the velocity of the hail relative to the cyclist and At what angle are the hailstones falling relative to the cyclist?

Solution :

The velocity of the hailstone falls is V_h=2\hat{i}-6\hat{k}\text{ m/s}

The velocity of the cyclist travels through the hail is V_c=10\hat{i} \text{ m/s}

The velocity of the hail relative to the cyclist is given by,

V_{hc}=V_h-V_c

Substitute the value in the formula,

V_{hc}=2\hat{i}-6\hat{k}-10\hat{i}

V_{hc}=-8\hat{i}-6\hat{k}

So, The velocity of the hail relative to the cyclist is V_{hc}=-8\hat{i}-6\hat{k}

Now, The angle of hails falling relative to the cyclist is given by

\theta = \tan^{-1}(\frac{-6}{-8})

\theta = \tan^{-1}(\frac{3}{4})

\theta = 36.86^\circ

So, The angle at which hailstones falling relative to the cyclist is  \theta = 36.86^\circ

4 0
3 years ago
The question is in the photo
Art [367]

Answer:

A or B.

A seems like best answer so far to me.

Step-by-step explanation:

Hope this helps!

6 0
3 years ago
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