A factory machine produces kilograms of chocolate every minutes. At what rate does the machine produce chocolate?

Mathematics

2 answers:

ICE Princess25 [194]3 years ago

8 0

The question says kilograms every minutes, so it's C or D. The answers on A and B same

slavikrds [6]3 years ago

3 0

Answer:

Its C i got it right

Step-by-step explanation:

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If function g has the factors (x - 7) and (x + 6), what are the zeros of function g?

vagabundo [1.1K]

The zeroes of the function will be equal to ( 7, -6 ).

<h3>What is a quadratic equation?</h3>

It is a polynomial with a degree of 2 or the maximum power of the variable is 2 in quadratic equations. It has two solutions as its maximum power is 2.

Given function:-

( x- 7 ) ( x+ 6 )

As we can see that the quadratic equation in the factorized form is ( x - 7 ) ( x+ 6 ) so we will equate each factor to zero.

( x- 7 ) = 0

x = 7

( x+ 6 ) = 0

x = -6

Therefore zeroes of the function will be equal to ( 7, -6 ).

To know more about quadratic equations follow

brainly.com/question/1214333

#SPJ1

8 0

2 years ago

Read 2 more answers

1.What is the equation of the line perpendicular to that passes through ? Write your answer in slope-intercept form. Show your

Juliette [100K]

Answer:

1. Use a compass to make arc marks which intersect above and below then connect.

2. $y=\frac{1}{3}x + 2$

Step-by-step explanation:

1. To construct a perpendicular line, use a compass to draw arc marks from one end of the segment through point P. Then repeat this again at the other end. This means at point P there will be two intersecting arc marks. Repeat the process down below with the same radius as used above. Then connect the two intersections.

2. The point slope form of a line is $(y-y_1)=m(x-x_1)$ where $x_1=-3\\y_1=1$ . We write

$(y-1)=m(x--3)\\(y-1)=m(x+3)$

Since the line is to be perpendicular to the line shown it will have the negative reciprocal to the slope of the function 3x+y =-8. To find m, rearrange the function to be y=-8-3x. The slope is -3 and the negative reciprocal will be 1/3.

$(y-1)=\frac{1}{3}(x+3)$