1.) 504
2.) 44
3.) 200
4.) 84
5.) 108
6.) 288
Answer:
15.87% probability that a randomly selected individual will be between 185 and 190 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a randomly selected individual will be between 185 and 190 pounds?
This probability is the pvalue of Z when X = 190 subtracted by the pvalue of Z when X = 185. So
X = 190



has a pvalue of 0.8944
X = 185



has a pvalue of 0.7357
0.8944 - 0.7357 = 0.1587
15.87% probability that a randomly selected individual will be between 185 and 190 pounds
Answer:
(2, 1 )
Step-by-step explanation:
Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
(
,
)
Here (x₁, y₁ ) = (7, 3) and (x₂, y₂ ) = (- 3, - 1) , then
midpoint = (
,
) = (
,
) = (2, 1 )
Answer:
3/5
Step-by-step explanation:
60% means 60 out of 100. For example if you get 60 marks in an exam of 100 marks. This means you got 60% marks.
Which is 60/100. This fraction can further be reduced to 6/10 [divide both numerator and denominator by 10)
6/10 = 3/5 [divide both numerator and denominator by 2)
So, the reduced form of 60% =3/5