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Deffense [45]
3 years ago
5

Use the given information to find the p​-value. ​Also, use a 0.05 significance level and state the conclusion about the null hyp

othesis​ (reject the null hypothesis or fail to reject the null​ hypothesis). With Upper H 1​: pnot equalsthree fifths ​, the test statistic is zequals0.78.
Mathematics
1 answer:
Hatshy [7]3 years ago
7 0

Answer:

We can assume that the statistic is z_{calc}=0.78

p_v = 2* P(z>0.78) = 0.435

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of interest is not different from 3/5

Step-by-step explanation:

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is equal to 3/5 or not.:  

Null hypothesis:p=3/5  

Alternative hypothesis:p \neq 3/5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

We can assume that the statistic is z_{calc}=0.78

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:

p_v = 2* P(z>0.78) = 0.435

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of interest is not different from 3/5

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What two numbers have a difference of 5 and a product of 3.36
iris [78.8K]
X-y=5
xy=3.36
add y to both sides on first
x=5+y
sub that in other eqation
(5+y)y=3.36
expand
y^2+5y=3.36
minus 3.36 both sides
y^2+5y-3.36=0
use quadratic formula


for
ay^2+by+c=0
y= \frac{-b+/- \sqrt{b^2-4ac} }{2a}
for 1y^2+5y-3.36
y= \frac{-5+/- \sqrt{5^2-4(1)(-3.36)} }{2(1)}
y= \frac{-5+/- \sqrt{25+13.44} }{2}
y= \frac{-5+/- \sqrt{38.44} }{2}
y= \frac{-5+/- 6.2}{2}
y=-2.5+/-3.1
y=5.6 or 0.6
sub back

x=y+5
so
x=10.6 or 5.6


the numbers are either 10.6 and 5.6 or 0.6 and 5.6
wait,but 10.6 and 5.6 don't multiply to get 3.36 so that is an extrainiesous answer

answer is 0.6 and 5.6

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3 years ago
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2-15 1/3 - 7 1/4 = 8 1/12, 8 1/12 / 2= 4 1/4 and 3 5/6 is the answer.

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3 years ago
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