X(3, 4); scale factor = 7
2 answers:
You might be interested in
Remember, order of operations
exponent before multiply
so 4x^5/6=4 times x^5/6
simplify the x^5/6 first
remember
![x^\frac{m}{n}=\sqrt[n]{s^m}](https://tex.z-dn.net/?f=x%5E%5Cfrac%7Bm%7D%7Bn%7D%3D%5Csqrt%5Bn%5D%7Bs%5Em%7D)
so
![x^\frac{5}{6}=\sqrt[6]{x^5}](https://tex.z-dn.net/?f=x%5E%5Cfrac%7B5%7D%7B6%7D%3D%5Csqrt%5B6%5D%7Bx%5E5%7D)
so
![4x^\frac{5}{6}=4\sqrt[6]{x^5}](https://tex.z-dn.net/?f=4x%5E%5Cfrac%7B5%7D%7B6%7D%3D4%5Csqrt%5B6%5D%7Bx%5E5%7D)
<span />
exponent before multiply
so 4x^5/6=4 times x^5/6
simplify the x^5/6 first
remember
so
so
<span />
<h2>Answer:</h2>
The probability is:
It is given that:
An urn contains balls numbered 1 through 20.
A ball is chosen, returned to the urn, and a second ball is chosen.
This means that this is a case of a replacement.
Hence, one of the event is independent of the other.
Now we know that the probability to get a particular number of ball is:
( Since, there are total 20 balls and a ball of one particular number is just unique )
i.e.
Hence, the probability that the first and second balls will be a 8 is: