1.
20 pounds of strawberries
5 persons
20 ÷ 5 = 20 pounds ÷ 5 persons = 4 pounds per person
Answer: 4 is the pounds per person, how much each person received
2.
20 pounds of strawberries
5 pounds per person
20 ÷ 5 = 20 pounds ÷ 5 pounds/person= 4 persons
Answer: 4 is the number of people we're splitting among
Tenths place is the value of the 6
Answer:
- the number is -6.4
- 52 students were in each bus (but one)
- 1 quart
Step-by-step explanation:
1. Let the number be represented by n. Then ten times the number is 10n, and 8 more than that is 10n+8. The problem statement tells us this sum is -56:
10n +8 = -56
10n = -64 . . . . . . . subtract 8 from both sides
n = -6.4 . . . . . . . . . divide both sides by 10
The number is -6.4.
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2. First of all, you can tell there is an issue with this question because the sum of digits of 472 is 13 and the sum of those digits is 4. This tells you that dividing 472 by 9 will give a remainder of 4, not 5. One of the buses will not be filled. (This process of adding digits until you get a single digit is called "casting out nines". The remaining digit is the remainder from division by 9.)
Let b represent the number of students in each bus. Then the problem statement tells us ...
9b + 5 = 472
9b = 467 . . . . . . subtract 5
b = 467/9 = 51 8/9 . . . . almost 52
52 students rode in 8 of the buses; 51 students rode in the last bus.
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3. Let q represent the number of quarts of 6% solution. Then the total amount of Boric Acid in the mix is ...
15%×2 + 6%×q = 12%×(2+q)
Multiplying by 100 to clear the % signs, we have ...
15·2 +6q = 12(2+q)
30 +6q = 24 +12q . . . . . . eliminate parentheses
6 = 6q . . . . . . . . . . . . . . . . subtract 24+6q from both sides
1 = q . . . . . . divide by 6
1 quart of 6% solution must be used.
Answer:
I believe it is c
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given the expression

First, factor each denominator:
1. 
2. 
Now the expression is

Now, multiply the first numerator by (y-3) and the second by (y-4) and write the result as a fraction with denominator 

This fraction cannot be simplified more.