The question is incomplete since the data is missing from it. I am writing the complete question below:
The American Housing Survey reported the following data on the number of times that owner-occupied and renter-occupied units had a water supply stoppage lasting 6 or more hours in the past 3 months.
Number of Houses (1000s)
Number of Times Owner Occupied Renter Occupied
0 547 23
1 5,012 541
2 6,110 3,734
3 2,544 8,660
4 times or more 557 3,784
Do not round intermediate calculations. Round your answers to two decimal places.
a. Define a random variable x = number of times that owner-occupied units had a water supply stoppage lasting 6 or more hours in the past 3 months and develop a probability distribution for the random variable. (Let x = 4 represent 4 or more times.)
Answer:
<u>x f(x)
</u>
0 0.0370
1 0.3393
2 0.4137
3 0.1722
<u>4 0.0378</u>
Total 1
Step-by-step explanation:
Total no. of times owner occupied units had a water supply stoppage lasting 6 or more hours :
547000 + 5012000 + 6110000 + 2544000 + 557000 = 14770000
x = no. of times owner occupied units had a water supply stoppage.
P(x=0) = 547000/14770000
P(x=0) = 0.0370
P(x=1) = 5012000/14770000
P(x=1) = 0.3393
P(x=2) = 6110000/14770000
P(x=2) = 0.4137
P(x=3) = 2544000/14770000
P(x=3) = 0.1722
P(x=4) = 557000/14770000
P(x=4) = 0.0378
<u></u>
<u>x f(x)
</u>
0 0.0370
1 0.3393
2 0.4137
3 0.1722
<u>4 0.0378</u>
Total 1
