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Hoochie [10]
3 years ago
5

Could someone help me? Why does x^4 * x^-4 = 1?

Mathematics
2 answers:
Alika [10]3 years ago
7 0

Answer:

Step-by-step explanation:

when you have a negative exponent, you are going to have a fraction. Example: 2^4 * 2^-4= 2^4 is 16 2^-4 is 1/16.

You get the 16 but because it was a negative exponent, the 16 goes on the bottom. 16 as a fraction is 16/1.

When you multiply 16/1 and 1/16. It comes up to 16/16 or 1.

Does this help?

Advocard [28]3 years ago
3 0

Answer:

below

Step-by-step explanation:

We can use the product rule of exponents to solve [ x^y * x^z = x^y+z ].

x^4 * x^-4 = 1

x^4+(-4) = 1

x^0 = 1

1 = 1

Best of Luck!

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The difference of two supplementary angles is 32 degrees. what are the angles
Masteriza [31]
Supplementary means 180   

180-32=148    hope this helps
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3 years ago
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Solve the following quadratic equation by using the quadratic formula.
Bas_tet [7]

Answer:

B. \frac{-3}{4}±\frac{\sqrt{41} }{4}

Step-by-step explanation:

First, substitute the equation into the quadratic formula.

x=\frac{b+-\sqrt{(b^{2} )-4(a)(c)} }{2a}

x=\frac{-3+-\sqrt{(3)^2-4(-2)(4)} }{4}

Solve for x.

x= \frac{-3+-\sqrt{9+32} }{4}

x=\frac{-3+-\sqrt{41} }{4}

The answer is x= -\frac{3}{4}±\frac{\sqrt{41} }{4}

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3 years ago
Select all the simplified expression <br>​
sineoko [7]

Answer:

1 / 3^5

1/ 243

Step-by-step explanation:

3^4 ÷ 3^9

We know that a^b ÷ a^c = a^ ( b-c)

3 ^ ( 4-9)

3^ -5

We can rewrite this as a^-b = 1/ a^b

1 / 3^5

We know that 3^5 = 243

1/ 243

5 0
3 years ago
Read 2 more answers
10. Determine whether or not, vectors ui(1,-2, 0, 3), u2 = (2, 3,0,-1), u3 = (3,9,-4,-2) e R is a linear combination of the (2,-
vodka [1.7K]

If (2, -1, 2, 1) is a linear combination of the three given vectors, then there should exist c_1,c_2,c_3 such that

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or equivalently, there should exist a solution to the system

\begin{cases}c_1+2c_2+3c_3=2\\-2c_1+3c_2+9c_3=-1\\-4c_3=2\\3c_1-c_2-2c_3=1\end{cases}

Right away we get c_3=-\dfrac12, so the system reduces to

\begin{cases}c_1+2c_2=\dfrac72\\\\-2c_1+3c_2=\dfrac72\\\\3c_1-c_2=0\end{cases}

Notice that the first equation is the sum of the latter two. The third equation gives us

3c_1-c_2=0\implies 3c_1=c_2

so that in the second equation,

-2c_1+3c_2=\dfrac72\implies7c_1=\dfrac72\implies c_1=\dfrac12

which in turn gives

3c_1=c_2\implies c_2=\dfrac32

and hence the (2, -1, 2, 1) is a linear combination of the given vectors, with

\boxed{(2,-1,2,1)=\dfrac12(1,-2,0,3)+\dfrac32(2,3,0,-1)-\dfrac12(3,9,-4,-2)}

5 0
4 years ago
The graph of an equation with a negative discriminant always has what characteristic
Jet001 [13]

Answer:

See below.

Step-by-step explanation:

The zeroes of the equation will  not be real so the graph will not pass through the x-axis.

5 0
3 years ago
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