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Hoochie [10]
3 years ago
5

Could someone help me? Why does x^4 * x^-4 = 1?

Mathematics
2 answers:
Alika [10]3 years ago
7 0

Answer:

Step-by-step explanation:

when you have a negative exponent, you are going to have a fraction. Example: 2^4 * 2^-4= 2^4 is 16 2^-4 is 1/16.

You get the 16 but because it was a negative exponent, the 16 goes on the bottom. 16 as a fraction is 16/1.

When you multiply 16/1 and 1/16. It comes up to 16/16 or 1.

Does this help?

Advocard [28]3 years ago
3 0

Answer:

below

Step-by-step explanation:

We can use the product rule of exponents to solve [ x^y * x^z = x^y+z ].

x^4 * x^-4 = 1

x^4+(-4) = 1

x^0 = 1

1 = 1

Best of Luck!

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The given function : h(x) = 6 - x

We know that for any functions f(x) and g(x)

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Therefore , h*h (x)=h(x)\times h(x)

h*h (x)=(6-x)(6-x)=(6-x)^2

h*h (x)=(6)^2-2(6)(x)+x^2 [ Using identity   (a-b)^2=a^2+2ab+b^2 ]

h*h (x)=36-12(x)+x^2

\-------->\ h*h (x)=36-12(x)+x^2 Now, at x= 10 , we get

h*h (10)=36-12(10)+(10)^2

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hoped it helped

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