at is another way to write the expression p⋅(10−2) ? (10⋅2)−p 10⋅2−p (10⋅2)⋅p (p⋅10)−(p⋅2)
1 answer:
Answer:
(p ⋅ 10) − (p ⋅ 2)
Step-by-step explanation:
Try to substitute "p" with any number.
Let's say p = 2
So
p ⋅ (10 − 2)
2 ⋅ (10 − 2)
2 ⋅ (8)
= 16
Now for the other equations
(p ⋅ 10) − (p ⋅ 2)
(2 ⋅ 10) − (2 ⋅ 2)
(20) - (4)
= 16
(10 ⋅ 2) − p
(10 ⋅ 2) − 2
(20 ) − 2
= 18
10 ⋅ 2 − p
10 ⋅ 2 − 2
20 - 2
= 18
(10 ⋅ 2) ⋅ p
(10 ⋅ 2) ⋅ 2
(20) ⋅ 2
= 40
Only (p ⋅ 10) − (p ⋅ 2) has the same result as p ⋅ (10 − 2).
Cheers
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