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Lynna [10]
2 years ago
7

at is another way to write the expression ​ p⋅(10−2) ​ ? (10⋅2)−p 10⋅2−p (10⋅2)⋅p (p⋅10)−(p⋅2)

Mathematics
1 answer:
Ostrovityanka [42]2 years ago
7 0

Answer:

(p ⋅ 10) − (p ⋅ 2)

Step-by-step explanation:

Try to substitute "p" with any number.

Let's say p = 2

So

p ⋅ (10 − 2)

2 ⋅ (10 − 2)

2 ⋅ (8)

= 16

Now for the other equations

(p ⋅ 10) − (p ⋅ 2)

(2 ⋅ 10) − (2 ⋅ 2)

(20) - (4)

= 16

(10 ⋅ 2) − p

(10 ⋅ 2) − 2

(20 ) − 2

= 18

10 ⋅ 2 − p

10 ⋅ 2 − 2

20 - 2

= 18

(10 ⋅ 2) ⋅ p

(10 ⋅ 2) ⋅ 2

(20) ⋅ 2

= 40

Only (p ⋅ 10) − (p ⋅ 2) has the same result as p ⋅ (10 − 2).

Cheers

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Step-by-step explanation:

Given polynomials are:

x^2-x-4\\and\\x-5

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So,

(x-5)(x^2-x-4)\\=x(x^2-x-4)-5(x^2-x-4)\\=x^3-x^2-4x-5x^2+5x+20

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Keywords: Polynomials, Multiplication

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Thus the amount after 5 years amount simply is $3000 and compoundly is $3312.24

5 0
3 years ago
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