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kolbaska11 [484]
3 years ago
12

Two six-sided fair dice are rolled simultaneously. The probability that the sum of the two numbers rolled is greater than 3, giv

en that the sum of the numbers is not greater than 5, is . The probability that one of the numbers is a 6 and the sum of the two numbers is an odd number is .
Mathematics
1 answer:
Nezavi [6.7K]3 years ago
4 0
A) Possible outcomes are ...
  (1, 3), (1, 4), (2, 2), (2, 3), (3, 1), (3, 2), (4, 1)
for a total of 7 out of 36 outcomes that match your requirements.
  p(3 < sum ≤ 5) = 7/36

B) Possible outcomes are ...
  (6, 1), (6, 3), (6, 5), (1, 6), (3, 6), (5, 6)
for a total of 6 out of 36 outcomes that match your requirements.
  p(6 and odd) = 6/36 = 1/6
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Ana Participated in each charity walk she raise $.25 and each 1/2 That she walked the first day and I walked 11 miles a second d
Tresset [83]

<em><u>Question:</u></em>

Ana participated in a charity walk. She raised $0.25 for each 1/2 mile that she walked.The first day Ana walked 11 miles.The second day, she walked 14 miles.How much money did Ana raised?

<em><u>Answer:</u></em>

Ana raised $ 12.5

<em><u>Solution:</u></em>

From given question,

First day walk = 11 miles

Second day walk = 14 miles

<em><u>Let us first calculate the total distance she walked</u></em>

Total distance = first day walk + second day walk

Total distance = 11 + 14 = 25 miles

Thus she walked for 25 miles

Given that,

<em><u>She raised $0.25 for each 1/2 mile that she walked</u></em>

\frac{1}{2} \text{ mile} = 0.25 \text{ dollars }

Therefore, for 1 mile we get,

\frac{1}{2} \times 2 \text{ mile} = 0.25 \times 2 \text{ dollars }\\\\1 \text{ mile } = 0.5 \text{ dollars }

Now calculate for 25 miles

25 \text{ mile } = 25 \times 0.5 = 12.5 \text{ dollars }

Thus she raised $ 12.5

4 0
3 years ago
A book sold 37,900 copies in its first month of release. Suppose this represents
Pachacha [2.7K]
The answer is 73,990.0 hope i help
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Express the complex number in trigonometric form. -6 + 6 square root of 3 i ?
bagirrra123 [75]
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\bf r=\sqrt{(-6)^2+(6\sqrt{3})^2}\implies r=\sqrt{36+(6^2\cdot 3)}\implies r=\sqrt{144}&#10;\\\\\\&#10;r=12\leftarrow &#10;\\\\\\&#10;\theta =tan^{-1}\left( \frac{6\sqrt{3}}{-6} \right)\implies \theta =tan^{-1}\left( -\sqrt{3}\right)\implies \theta =&#10;\begin{cases}&#10;\frac{2\pi }{3}\leftarrow \\&#10;\frac{5\pi }{3}&#10;\end{cases}

now, notice, there are two valid angles for such a tangent, however, if we look at the complex pair, the "a" is negative and the "b" is positive, that means, "x" is negative and "y" is positive, and that only occurs in the 2nd quadrant, so the angle is in the second quadrant, not on the fourth quadrant.

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5 0
3 years ago
Rebecca was advised to invest her £12000 life savings in a special High
Evgesh-ka [11]

#a

#1st year

\\ \rm\Rrightarrow 12000+0.045(12000)=12540

#2nd year

\\ \rm\Rrightarrow 12540+0.05(12540)=13167

#3rd year

\\ \rm\Rrightarrow 13167+0.053(13167)=13864.85

#4th year

\\ \rm\Rrightarrow 13864.85+13864.85(0.049)=14544.2

#b

Total interest

\\ \rm\Rrightarrow 14544.2-12000=£ 2544.2

#c

Percentage

\\ \rm\Rrightarrow \dfrac{2544.2}{12000}\times 100

\\ \rm\Rrightarrow 21.2\%

3 0
2 years ago
Read 2 more answers
You are playing a board game with your little sister. Moves are determined by rolling 2 six-sided dice. The red die tells you th
enot [183]

Answer: The probability is 1/9.

Step-by-step explanation:

First, let's define the possible outcomes of each dice:

Red: Forward (4 times), Backward (2 times)

Green : {1, 1, 2, 2, 3, 4}

We want to find the probability of moving backward 2 spaces.

Then we need to find the probability of rolling a "backward" in the red dice, and a 2 in the green dice.

First, the probability of rolling a backward in the red dice is equal to the quotient between the number of outcomes that are "backward", and the total number of outcomes in the dice (there are 2 backwards and 6 outcomes in total), this is:

p1 = 2/6 = 1/3.

And the probability of rolling a 2 in the green dice is equal to the quotient between the number of outcomes with a 2, and the total number of outcomes. (The 2 appears two times, and there are 6 possible outcomes):

p2 = 2/6 = 1/3.

Now, the probability of both events happening at the same time is equal to the product of the individual probabilities, then the probability of moving backwards 2 spaces is:

P = p1*p2 = (1/3)*(1/3) = 1/9.

7 0
3 years ago
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