Answer:
1. CaCO3(s) <=> CaO(s) +CO2 (g) Delta H = +178 kJ/mol
Since Delta H is positive, it means the reaction is endothermic
a. An increase in temperature will will shift the equilibrium position to the right, thus forming more products
b. A decrease in the temperature will shift the equilibrium position to the left, thus forming more reactants
2. PCl3(g) + Cl2(g) <-> PCl5 (g) Delta H= -88 kJ/mol
From the above, Delta H is negative which implies exothermic reaction.
c. Increasing the temperature will shift the equilibrium position to the left, thus forming more reactants.
d. Decreasing the temperature will shift the equilibrium position to the right, thus forming more products
