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Fed [463]
3 years ago
5

A sprinter set a high school record in track and field, running 200.0 m in 21.7 s . What is the average speed of the sprinter in

kilometers per hour?
Chemistry
1 answer:
Yuliya22 [10]3 years ago
7 0

Given data:

Distance travelled (d)= 200.0 m

Time taken (t) = 21.7 s

To determine:

The average speed in km/hr

Calculation:

Convert distance from m to km

1000 m = 1 km

200.0 m = 1 km * 200.0 m/1000 m = 0.2 km

Convert time from sec to hours

3600 sec = 1 hour

21.7 sec = 1 hour * 21.7 sec/3600 sec = 6.027 *10^-3 hrs

Speed is defined as the amount of distance travelled per unit time

Speed = distance/time = 0.2 km/6.027*10^-3 hr

           = 33.18 km/hr (or 33.2 km/hr)

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Chlorophyll: green
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8 0
3 years ago
A student obtains a beaker containing a solution that is determined to have a hydrogen ion
OleMash [197]

Answer:

pH = 13.1

Basic

Explanation:

Step 1: Given data

Hydrogen ion concentration ([H⁺]): 6.7 × 10⁻¹⁴ M

Step 2: Calculate the pH of the solution

We will use the definition of pH.

pH = -log [H⁺]

pH = -log 6.7 × 10⁻¹⁴ = 13.1

  • When pH < 7, the solution is acid.
  • When pH = 7, the solution is neutral.
  • When pH > 7, the solution is basic.

Since pH > 7, the solution is basic.

6 0
3 years ago
2. How many grams of zinc will be formed if 32.0 g of copper reacts with zinc nitrate? Copper(I)nitrate is the other product.
Yakvenalex [24]

Answer:

16.46 g.

Explanation:

  • It is a stichiometry problem.
  • We should write the balance equation of the mentioned chemical reaction:

<em>2Cu + Zn(NO₃)₂ → Zn + 2Cu(NO₃).</em>

  • It is clear that 2.0 moles of Cu reacts with 1.0 mole of Zn(NO₃)₂ to produce 1.0 mole of Zn and 2.0 moles of Cu(NO₃).
  • We need to calculate the number of moles of the reacted Cu (32.0 g) using the relation:

<em>n = mass / molar mass</em>

  • The no. of moles of Cu = mass / atomic mass = (32.0 g) / (63.546 g/mol) = 0.503 mol.

<u><em>Using cross multiplication:</em></u>

2.0 moles of Cu produces → 1.0 mole of Zn, from the stichiometry.

0.503 mole of Cu produces → ??? mole of Zn.

  • The no. of moles of Zn produced = (1.0 mol)(0.503 mol) / (2.0 mol) = 0.2517 mol.

∴ The grams of Zn produced = no. of moles x atomic mass of Zn = (0.2517 mol)(65.38 g/mol) = 16.46 g.

3 0
3 years ago
How many grams Kl are needed to prepare 100.mL of 0.55M solution?​
Makovka662 [10]

Answer:

Explanation:

100mL = 0.1L

0.55 M = mol/0.1 L

mol = 0.055 mol

molar mass of KI = 165.998 g

0.055 * 165.998 = 9.13 g of KI

7 0
2 years ago
Which piece of glassware shown below is used to hold and dispense a solution of known concentration during a titration?
Musya8 [376]

Answer:

Answer C

Explanation:

Got it off of q**zlet ;)

4 0
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