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tankabanditka [31]
3 years ago
5

Translate the following and explain where these examples could be

Mathematics
1 answer:
ki77a [65]3 years ago
5 0
A) x-6; you have x amount of money and pay 6 dollars for a hat.
b) 2(x2);
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6. John took Ms. Wisth out for sushi and is NOT a cheapskate. Their total sushi bill was $75.68. John
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I think the answer would be $9.46 left as a tip for the waiter.
6 0
2 years ago
Read 2 more answers
In a data set, Q1 is 24, and Q3 is 36. Regarding the same data, use the "IQR x 1.5" method to determine which of the following n
STatiana [176]

Answer:

The answer is none triangle

Step-by-step explanation:

we know that

The sum of internal angles of a triangle must be equal to  

In this problem we have three angles, each measuring  

so

The total sum of the three angles is equal to  

therefore

The answer is none triangle

6 0
2 years ago
What is the fully factored form of the expression 45x²y2 + 18x3
Llana [10]

Answer:

9x^2(5y^2 + 2x).

Step-by-step explanation:

First find the Greatest Common Factor of the 2 terms.

GCF of 18 and 45 = 9

GCF of x^2 and x^3 = x^2.

The complete GCF is therefore 9x^2.

So, dividing each term by the GCF, we obtain:

9x^2(5y^2 + 2x).

4 0
2 years ago
Prove that (Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A
iVinArrow [24]

Answer:

The answer is below

Step-by-step explanation:

We need to prove that:

(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.

Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.

Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

\frac{\sqrt{secA-1} }{\sqrt{secA+1} } +\frac{\sqrt{secA+1} }{\sqrt{secA-1} } =\frac{(\sqrt{secA-1)}(\sqrt{secA-1})+(\sqrt{secA+1)}(\sqrt{secA+1}) }{(\sqrt{secA+1})(\sqrt{secA-1}) } \\\\=\frac{secA-1+(secA+1)}{\sqrt{sec^2A-secA+secA-1} } \\\\=\frac{2secA}{\sqrt{sec^2A-1} } \\\\=\frac{2secA}{\sqrt{tan^2A} } \\\\=\frac{2secA}{tanA} \\\\=\frac{2*\frac{1}{cosA} }{\frac{sinA}{cosA} }\\\\= 2*\frac{1}{cosA}*\frac{cosA}{sinA}\\\\=2*\frac{1}{sinAA}\\\\=2cosecA

7 0
3 years ago
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