Y=58
Y+14/6=12
Cross multiply to solve
So y+14=72 then subtract 14 so
Y=58
Answer:
x = 8√2
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Trigonometry</u>
- [Right Triangles Only]: Pythagorean Theorem: a² + b² = c²
Step-by-step explanation:
<u>Step 1: Define</u>
We are given a right triangle. We can use PT to solve for the missing length.
<u>Step 2: Identify Variables</u>
Leg <em>a</em> = 8
Leg <em>b</em> = 8
Hypotenuse <em>c</em> = <em>x</em>
<u>Step 3: Solve for </u><em><u>x</u></em>
- Substitute [PT]: 8² + 8² = x²
- Exponents: 64 + 64 = x²
- Add: 128 = x²
- Isolate <em>x</em>: 8√2 = x
- Rewrite: x = 8√2
Answer:
f(x)=3a+6
Step-by-step explanation:
f(x)=3(a+2)
=3a+6
Answer:
Read below.
Step-by-step explanation:
A perfect cube is a number cubed (If that makes sense). Such as 3³ will equal a perfect cube because it's being multiplied by itself 3 times. 3×3×3=9. It will work for any whole number. You can check if a given number is a perfect cube by using the cube root (![\sqrt[3]{x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D)
).
Hope it makes sense!
