3 years ago

What is 12 over 3 as a proper fraction?

Mathematics

1 answer:

AysviL [449]3 years ago

6 0

That would be 4 :D , basically 12 divided by 3

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Please help me, Identify each pair of angles named below as adjacent angles or vertical angles.

jarptica [38.1K]

Adjacent angles:

-ADB and BDC

-BDC and CDE

-CDE and EDF

-FDG and GDA

-GDA and ADB

Vertical angles:

-GDA and CDE

-FDE and ADB

-GDF and BDC

Hope this helps! :)

5 0

3 years ago

HELP PLEASE !?!? I suck at math

Anna35 [415]

To graph the equation, plot a few points then connect then with a line.

f(x) = 440 - 55x

Plug in numbers for x to get the y value.

f(0) = 440
f(1) = 385
f(2) = 330
f(3) = 275
f(4) = 220
f(5) = 165

So when you graph these points, the y intercept is y = 440 because the graph crosses the y axis at (0, 440).

The x intercept is where the graph crosses the x axis. This happens when y = 0.

0 = 440 - 55x. Solve for x.

55x = 440
x = 8

So the x intercept is x = 8

7 0

3 years ago

X - 5(x - 1) = x - (2x - 3)

m_a_m_a [10]

X=2/3 I hope this helps

3 0

3 years ago

Read 2 more answers

1. If A = {a, b, c, d}, B={c, d, e, f}, C={x, y, z} find (A-B)

vitfil [10]

Answer

here

A={a,b,c,d}

B={c,d,e,f}

C={x,y,z}

A-B={e,f}

8 0

1 year ago

Which expression is equivalent to -18a^-2b^5/-12a^-4b^-6

crimeas [40]

Answer:

c. 3a^2b^11/2

Step-by-step explanation:

The applicable rule of exponents is ...

(a^b)/(a^c) = a^(b-c)

$\dfrac{-18a^{-2}b^5}{-12a^{-4}b^{-6}}=\dfrac{-18}{-12}a^{-2-(-4)}b^{5-(-6)}=\boxed{\dfrac{3a^2b^{11}}{2}}$

3 0

2 years ago