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leonid [27]
3 years ago
13

What is the IUPAC name for the following compound? Question 10 options: 1-methyl-3-cyclohexene methylcyclohexene 5-methylcyclohe

xene 1-methyl-4-cyclohexene 4-methylcyclohexene

Chemistry
1 answer:
Korolek [52]3 years ago
4 0

Answer:

  • <u><em>4-methylcyclohexene (the last choice)</em></u>

Explanation:

The compound is an alkene (cycloalkene), with a methyl group as substituent (it substitutes one hydrogen in the carbon chain).

The IUPAC's rules state that the location of the carbon-carbon double bond in the structure is indicated by specifying the number of the carbon atom at which the C=C bond starts, assigning the lowest possible number to the double bond: this in this case is number 1.

<em>Cyclohexene</em> is the main chain and mehtyl is a substituent, as already said.

So, the name 1-methyl-3-cychlohexene is not valid (position 1 is for the carbon-carbon double bond).

The name methycyclohexene is not valid because it is not telling the position of methylgroup.

The name 5-methylcyclohexene is not valid because the position five should be named 2 in the cyclohexene (you must use the smallest number), so the name should be 2-methyl... instead of 5 methyl...

1-methyl-4cyclohexene is not valid because, as said, the position 1 is reserved for the carbon-carbon double bond.

Only 4-methylcyclohexene is a valid name.

The file attached shows the structure. I have added numbers on the carbons of the main chain to show you how that the methyl group is in the positiion number 4.

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0.025 M will be the resulting concentration

Explanation:

To find the resulting concentration we use the following formula:

initial concentration × initial volume = final concentration × final volume

initial concentration = 0.15 M

initial volume = 2 mL

final concentration = ?

final volume = 10 + 2 = 12 mL

0.15 × 2 = final concentration × 12

final concentration = (0.15 × 2) / 12

final concentration =  0.025 M

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Which of the following was NOT among Democritus's ideas?
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You have 16.0 g of some compound and you perform an experiment to remove all of the oxygen, 11.2 g of iron is left. What is the
oksian1 [2.3K]

The empirical formula of this compound is equal to Fe_{2}O_3.

<h3>Empirical formula</h3>

To calculate the empirical formula of a compound, it is necessary to know the number of moles present.

Therefore, we will use the molar mass of iron and oxygen to find the amount of moles, so that:

MM_O = 16g/mol\\MM_Fe = 55.8g/mol

                                        MM = \frac{m}{mol}

  • Oxygen

                                            16 = \frac{4.8}{mol}

                                            mol = 0.3

  • Iron

                                   

                                               55.8 = \frac{11.2}{mol}

                                               mol = 0.2

Finally, as the empirical formula is composed of integers numbers of moles, just multiply the values ​​by the smallest common factor to transform into an integer, so that:

                                       O =>  0.3 \times 10 = 3moles

                                       Fe => 0.2 \times 10 = 2moles

So, the empirical formula of this compound is equal to Fe_{2}O_3

Learn more about empirical formula in: brainly.com/question/1363167

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