Chemical property on this
Answer:
0.492 J/g °C
General Formulas and Concepts:
<u>Thermodynamics</u>
Specific Heat Formula: q = mcΔT
- <em>q</em> is heat (in J0
- <em>m</em> is mass (in g)
- <em>c</em> is specific heat (in J/g °C)
- <em>ΔT</em> is change in temperature (in °C)
Explanation:
<u>Step 1: Define</u>
<em>Identify variables</em>
[Given] <em>q</em> = 45.0 J
[Given] <em>m</em> = 8.10 g
[Given] <em>ΔT</em> = 24.3 °C - 13.0 °C = 11.3 °C
[Solve] <em>c</em>
<em />
<u>Step 2: Solve for </u><em><u>c</u></em>
- Substitute in variables [Specific Heat Formula]: 45.0 J = (8.10 g)c(11.3 °C)
- Multiply: 45.0 J = (91.53 g °C)c
- Isolate <em>c</em>: 0.491642 J/g °C = c
- Rewrite: c = 0.491642 J/g °C
<u>Step 3: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.491642 J/g °C ≈ 0.492 J/g °C
<span>The number of valence electrons from the electron configuration,write 1s², 2s² 2p⁶, 3s² 3p⁴.
The "big" numbers are the principal quantum numbers (n) which correspond to the major energy levels, and sub-scripted numbers are the number of electrons in the sub-energy level.
</span><span>For sulfur, the highest principal quantum number is 3, and there are 6 electrons in the 3s² and 3p⁴ sublevels. </span>
Answer:
Gravity
Explanation:
gravity forces the ball to eventually stop bouncing
