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salantis [7]
3 years ago
14

Adrienne has several receipts from recent transactions that she entered in her records. The receipts include an ATM receipt for

a $60.00 withdrawal (plus a $2.00 transaction fee), a grocery store receipt for $32.50, and a $1,200 paycheck deposit slip. When she finishes entering her transactions, Adrienne realizes that her balance is incorrect. Assuming that Adrienne’s beginning account balance was $320.00, why is her balance incorrect?
a. Adrienne forgot to include the $2.00 ATM transaction fee.
b. Adrienne did not use $320.00 as her starting balance.
c. Adrienne deducted $23.50 from her balance instead of $32.50. d. Adrienne did not enter her ATM withdrawal correctly.
Mathematics
2 answers:
Rina8888 [55]3 years ago
6 0

Answer:

D.

Step-by-step explanation:

Adrienne did not enter her ATM withdrawal correctly.

svp [43]3 years ago
3 0

Answer:D

Step-by-step explanation:    :)

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14(5-1/5×25)+2÷4×1 How Do I Evaluate This Expression ?
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How was y'all day. I hope it is good
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4 0
3 years ago
Coach Evans recorded the height, in inches of each player on his team. The results are shown.
marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile (Q_1)

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile (Q_3)

Terms in arranged in ascending order:

57,60,60,61,62,62,63,63,64

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

Q_1 is median of terms 57,60,60,61

Number of terms (n) = 4

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60

So, Q_1=60

So, 25% of the heights of a team is less than 60 inches

Q_3 is the median of terms 62,63,63,64

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63

So, Q_3=63

So, 75% of the heights of a team is less than 63 inches

Interquartile range = Q_3-Q_1=63-60=3

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0
3 years ago
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The required equation of the line passing the coordinates will be y = 3/4x - 1/4

<h3 /><h3>Equation of a line</h3>

The standard equation of a line is expressed as y= mx + b

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b is the y-intercept

Given the coordinate points on a line (3, 2) and (-1, -1)

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The required equation of the line passing the coordinates will be y = 3/4x - 1/4

Learn more on equation of a line here: brainly.com/question/18831322

#SPJ1

7 0
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