SOMEONE PLEASE HELP ME!!!
1 answer:
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A square pyramid is called like so because its base is a square.
notice this one, its base is a 0.4x0.4 square, and the triangular faces have a base of 0.4 and an altitude or height of 5.
so we can simply get the area of the base and all four triangular faces and sum them up, and that's the surface area of the pyramid.
![\bf \stackrel{\textit{squarish base}}{(0.4\cdot 0.4)}~~+~~\stackrel{\textit{4 triangles}}{4\left[\cfrac{1}{2}(0.4)(5) \right]}\implies 0.16~~+~~4\implies 4.16](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bsquarish%20base%7D%7D%7B%280.4%5Ccdot%200.4%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7B4%20triangles%7D%7D%7B4%5Cleft%5B%5Ccfrac%7B1%7D%7B2%7D%280.4%29%285%29%20%20%5Cright%5D%7D%5Cimplies%200.16~~%2B~~4%5Cimplies%204.16)
notice this one, its base is a 0.4x0.4 square, and the triangular faces have a base of 0.4 and an altitude or height of 5.
so we can simply get the area of the base and all four triangular faces and sum them up, and that's the surface area of the pyramid.
Answer:
Step-by-step explanation:
Hello There!
<u>Geometry</u>
The angles shown represented by the expressions (11x + 5) and (5x+59) are vertical angles
Vertical angles are congruent so we can use this equation to solve for x
<u>Basic Algebra</u>
11x + 5 = 5x + 59
step 1 subtract 5x from each side
5x - 5x cancels out
11x - 5x = 6x
now we have 6x + 5 = 59
step 2 subtract each side by 5
5 - 5 cancels out
59 - 5 = 54
now we have 54 = 6x
step 3 divide each side by 6
6x/6=x
54/6=9
we're left with x = 9
now we want to plug in 9 into x for one of the expression
11(9) + 5
11 * 9 = 99
99 + 5 = 104
so we can conclude that the measure of the angle labeled ( 11x + 5 ) is 104 degrees
Now we need to find z
<u>Geometry</u>
The angle with a measure of 104 and angle Z are supplementary angles meaning that the sum of the two is 180
So to find z we subtract the known angle (104) from 180
180 - 104 = 76
so we can conclude that z = 76