Answer:
Step-by-step explanation:
If 5! is equal to 5 × 4 × 3 × 2 × 1 and 6! is equal to 6 × 5 × 4 × 3 × 2 × 1, then 4! is equal to 4 × 3 × 2 × 1. Thus, 4! = 4 × 3 × 2 × 1, which can simplify to 24. 4! = 24.
is basically 4 × 4 × 4 × 4, which can simplify to 256.
So, 
= 
. can simplify to . Therefore, = .
Answer:
Your answer of 10 x 12 - 14 +2+15 =123
Answer:
48
Step-by-step explanation:
138-90(right angled triangle)=48
Answer:
4 5/6
Step-by-step explanation:
since 6x10-2 is 58, and 2x10-8 is 12, divide 58 by 12 to get 4 5/6
Sample space is 36C4
Now, we want to know all of the combinations that have 1 digit in it.
So, we can have one here:
1XXX
X1XX
XX1X
XXX1
But we have 10 different digits to choose from. So, we need to introduce the combination term, nCr, where n is a list of all digits and r is how many we want.
Since we only want one, we will need 10C1 for the number of digits. But we need to choose three lowercases, so it becomes 10C1 × 26C3
Since it's a probability question, we need to divide that by our sample space, 36C4, and our percentage becomes 44%
