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2 years ago

I need help i dont get word problems how do you put this in an equation.

Mathematics

2 answers:

juin [17]2 years ago

8 0

I think you want a relationship between the number of lawns mowed and the income from doing it.

I = income

L = lawns

I = 8.50 * L If the question tells you how many lawns he mowed, just put that in for L

L = 8 means he mowed 8 lawns. This is just a made up number.

I = 8.50 * 8

I = 68 dollars from mowing 8 lawns.

SpyIntel [72]2 years ago

6 0

Well, we could make the number of lawns he mowed as 'L'

In this case, the total money that Gavin makes is 8.5L

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2 years ago

1. Which of the following is NOT a true statement?

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2 years ago

Read 2 more answers

Solve the equation (linear equation)<br><br> <img src="https://tex.z-dn.net/?f=8%5E%7B2x%2B7%7D%20%3D%20%28%5Cfrac%7B1%7D%7B32%7

Minchanka [31]

Answer: $x=-1$

Step-by-step explanation:

By the negative exponent rule, you have that:

$(\frac{1}{a})^n=a^{-n}$

By the exponents properties, you know that:

$(m^n)^l=m^{(nl)}$

Therefore, you can rewrite the left side of the equation has following:

$(\frac{1}{8})^{-(2x+7)}=(\frac{1}{32})^{3x}$

Descompose 32 and 8 into its prime factors:

$32=2*2*2*2*2=2^5\\8=2*2*2=2^3$

Rewrite:

$(\frac{1}{2^3})^{-(2x+7)}=(\frac{1}{2^5})^{3x}$

Then:

$(\frac{1}{2})^{-3(2x+7)}=(\frac{1}{2})^{5(3x)}$

As the base are equal, then:

$-3(2x+7)=5(3x)$

Solve for x:

$-6x-21=15x\\-21=15x+6x\\-21=21x\\x=-1$

8 0

2 years ago

A sample of 47 observations is selected from a normal population. The sample mean is 30, and the population standard deviation i

erma4kov [3.2K]

Answer:

We accept the null hypothesis and reject the alternate hypothesis. There is no evidence to conclude that the population mean is greater than 29. The population mean is less than or equal to 29.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 29

Sample mean, $\bar{x}$ = 30

Sample size, n = 47

Alpha, α = 0.05

Population standard deviation, σ = 5

First, we design the null and the alternate hypothesis

$H_{0}: \mu \leq 29\\H_A: \mu > 29$

a) This is a one-tailed test because the alternate hypothesis is in greater than direction.

We use One-tailed z test to perform this hypothesis.

b) $z_{stat} > z_{critical}$ , we reject the null hypothesis and accept the alternate hypothesis and if $z_{stat} < z_{critical}$ , we accept the null hypothesis and reject the alternate hypothesis.

c) Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{30 - 29}{\frac{5}{\sqrt{47}} } = 1.37$

d) Now, $z_{critical} \text{ at 0.05 level of significance } = 1.64$

Since,

$z_{stat} < z_{critical}$

We accept the null hypothesis and reject the alternate hypothesis. There is no evidence to conclude that the population mean is greater than 29. The population mean is less than or equal to 29.

e) P-value is 0.0853

On the basis of p value we again accept the null hypothesis.

5 0

3 years ago