Question

Use the fundamental identities to verify

Answer 1

Answer:

see below

Step-by-step explanation:

6 cot ^2 (y) ( sec^2 (y) -1) = 6

We know that ( sec^2 (y) -1) = tan ^2(y)

6 cot ^2 (y) tan ^2 (y) = 6

We know cot = cos/ sin   and tan = sin / cos

6 cos/ sin ^2 (y) sin/cos ^2 (y) = 6

6 ( 1) = 6

6=6

Answer 2

Answer:

See below

Step-by-step explanation:

$6\cot^2(\gamma)(\sec^2(\gamma)-1)=6\\\\\\\\cot^2(\gamma)(\sec^2(\gamma)-1)=1\\\\\\\dfrac{\cos^2(\gamma)}{\sin^2(\gamma)}\left(\dfrac{1}{\cos^2(\gamma)}-1\right)=1\\\\\\\dfrac{1}{\sin^2(\gamma)}-\dfrac{\cos^2(\gamma)}{\sin^2(\gamma)}=1 \\\\\\\csc (\gamma) - \cot (\gamma)=1 \\\\\\1=1 \\\\QED$

Hope this helps!