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trasher [3.6K]
3 years ago
13

Find the number one-third of the way from 1/6 to 4/5.

Mathematics
1 answer:
masya89 [10]3 years ago
3 0
I got u with this it really easy
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Dany scored 93 in physics, 88 in mathematics, and a score in chemistry that is double his score in geography. The average score
Leno4ka [110]

Answer:

90

Step-by-step explanation:

Let x be Dany's score in geography. His score in chemistry is double his score in geography and it is equal to

2 x

The average of all four scores is 79. Hence

(93 + 88 + x + 2 x) / 4 = 79

Multiply both sides of the equation by 4

4×(93 + 88 + x + 2 x) / 4 = 4×79

Simplify

93 + 88 + x + 2 x = 316

Group like terms

3 x + 181 = 316

Solve for x

3 x = 135

3 x / 3 = 135 / 3

x = 45

score in geography = x = 45

score in chemistry = 2 x = 2 × 45 = 90

Hope it helped u if yes mark me BRAINLIEST!

Tysm!

6 0
3 years ago
Read 2 more answers
Given the following geometric sequence, find the common ratio: {16, 64, 256, ...}.
Anettt [7]

Answer:

The common ratio is 4

Step-by-step explanation:

We need to divide a term by the previous term to find the common ratio in a geometric sequence:

64 ÷ 16 = 4

256 ÷ 64 = 4

By doing it twice we can confirm that the common ratio is 4

8 0
3 years ago
Read 2 more answers
(4x + 3) (3x^2 - 5x + 6)
Liula [17]

Answer:

12x^3 - 11x^2 + 9x + 18

Step-by-step explanation:

12x^3 - 20x^2 + 24x + 9x^2 -15x + 18

Combine like terms

12x^3 - 11x^2 + 9x + 18

4 0
3 years ago
Factor the expression 26x + 13
bogdanovich [222]
Answer
Factor 13 out of 26x+13
= 13( 2x+1)
6 0
3 years ago
Please help! <br> Simplify. Your answer should contain only positive exponents.
maxonik [38]

Answer:

\frac{1}{4k^3}

Step-by-step explanation:

It's already in a form that only ha positive exponents.  Just to state it though you could rewrite it as k*(4k^{4})^{-1} or k*4^{-1}*k^{-4}  The question asks for positive exponents though so yu don't need to do that.

You also need to know \frac{x^a}{x^b}=x^{a-b} so in this case \frac{k}{k^4}=\frac{k^1}{k^4} =k^{1-4}=k^{-3}=\frac{1}{k^3}

so \frac{k}{4k^4}=\frac{1}{4}*\frac{k}{k^4}=\frac{1}{4}*\frac{1}{k^3}=\frac{1}{4k^3}

3 0
3 years ago
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