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3 years ago

7

Proportional Relationships

1 answer:

STALIN [3.7K]3 years ago

7 0

the answer is the first one

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4 years ago

The equation of a circle whose center is at (4, 0) and radius is length 2√(3) is

soldier1979 [14.2K]

ANSWER

${(x - 4)}^{2} + {y}^{2} = 12$

EXPLANATION

The equation of a circle given the center (h,k) and radius r is given by:

${(x - h)}^{2} + {(y - k)}^{2} = {r}^{2}$

The circle has center (4,0) and radius

$r = 2 \sqrt{3}$

We substitute the center and radius to get,

${(x - 4)}^{2} + {(y - 0)}^{2} = {(2 \sqrt{3)} }^{2}$

${(x - 4)}^{2} + {(y - 0)}^{2} = 12$

${(x - 4)}^{2} + {y}^{2} = 12$

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3 years ago