by the double angle identity for sine. Move everything to one side and factor out the cosine term.
Now the zero product property tells us that there are two cases where this is true,
In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of
, so
where
![n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}](https://tex.z-dn.net/?f=n%5B%2Ftex%20%5Dis%20any%20integer.%5C%5CMeanwhile%2C%5C%5C%5Btex%5D10%5Csin%20x-3%3D0%5Cimplies%5Csin%20x%3D%5Cdfrac3%7B10%7D)
which occurs twice in the interval
for
and
. More generally, if you think of
as a point on the unit circle, this occurs whenever
also completes a full revolution about the origin. This means for any integer
, the general solution in this case would be
and
.
Answer:
The answer is c. hope this helps
Step-by-step explanation:
Answer:
After 5 weeks.
Step-by-step explanation:
Westley starts with $85 and saves $5 per week. So:
Buttercup starts with $10 and saves $20 per week. So:
When they have the same amount of money, the two equations will be equal to each other. Therefore:
Solve for x. Subtract 10 from both sides:
Subtract 5x from both sides:
Divide both sides by 15:
Westley and Buttercup will have the same amount of money after 5 weeks.
The total cost of the camera is $268.26
A down payment of $12 was paid so he now owes $256.26
Every 6 months Emil has to pay:
256.26 / 6 = 42.71
Therefore, each moth, Emil has to pay $42.71
Answer:
1/(√x-5)*(√x+5)/(√x+5)
Step-by-step explanation:
1/(√x-5)*(√x+5)/(√x+5)
